Toy car executing a vertical loop

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To determine the minimum speed a toy car must have at the bottom of a vertical loop with a radius of 15 cm, it's essential to apply the principles of energy conservation and centripetal acceleration. The car must maintain a certain speed at the top of the loop to avoid losing contact with the track, which occurs when the normal force is zero. By using the work-energy theorem, the kinetic energy at the bottom can be equated to the potential energy at the top to find the necessary velocity. Additionally, analyzing the forces acting on the car at the top reveals the required centripetal acceleration to keep it on the track. Understanding these dynamics is crucial for solving the problem effectively.
Jared C
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Homework Statement


A small toy car slides down an elaborate track. At one point during this trip, the car will go around a vertical loop with radius 15cm as shown. What is the minimum speed the car must have at the bottom of the loop in order to make it all the way around the loop without falling off?

Homework Equations


Ki + Ui + WNC = Kf + Uf
K = (1/2)mv2
Ui = mgh
W = Fdcosx
F = ma
ac = v2/r

The Attempt at a Solution


I tried using the work-energy theorem, using (1/2)mv2 = mgh to find the velocity needed for the car to have zero potential energy at the top of the loop, but I know this problem also involves centripetal acceleration and that the car would also need to have some velocity at the top of the loop to finish going around it (zero velocity would cause it to fall downward), but I have no clue how to use this to solve the problem
 
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The key to this problem is that when the car reaches the top of the loop, it is at the speed where it is just at the point where it starts to lose contact with the ramp. In other words, the normal force from the track is equal to 0. So at the bottom of the ramp, you could define that as the point where all of the car's energy is kinetic energy (0 potential energy). So you would have to calculate what speed it would be where the car just starts to lose contact at the top of the loop and work from there. I hope that helps.

Welcome to Physics Forums.
 
Jared C said:
zero velocity would cause it to fall downward
Quite so.
Draw a free body diagram for it when at the top of the loop. What forces act on it? What is the net force? What acceleration needs to result?
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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