1. The problem statement, all variables and given/known data A bead slides without friction around a loop–the–loop (see figure below). The bead is released from rest at a heighth = 3.60R. (a) What is its speed at point ? (Use the following as necessary: the acceleration due to gravity g, and R.) v = _________________ (b) How large is the normal force on the bead at point if its mass is 4.70 grams? Find the magnitude and direction. 2. Relevant equations u = mgh k = .5mv^2 ui + ki = uf + kf g = 9.8 m/s^2 h = 3.60R 3. The attempt at a solution For a, I don't know how much farther I can go. the farthest I've gotten is this: where h = 3.60R ui + ki = uf + kf mgh + 0 = .5mv^2 + mgh gh = .5v^2 + gh If I subtract gh from the right though, I'll get 0... which is obviously not the answer here. So I need major help there. As for b, I know the direction is downward. It's upside down so if I flip the entire diagram, I see that normal force is really pointing down. As for the first part, I just converted grams to kg, then multiplied by 9.8 m/s^2. However, the website I'm entering the answer into keeps saying I'm wrong when I type in when I input my answer 0.04606 N, so I'm not sure what's up there... I also tried 0.0461 N, and still no dice... Thanks for any help!