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Trajectory (Quick Question) -- where would it be maximum speed?

  1. Nov 30, 2014 #1
    • Warning: Posting template must be used in homework sections.
    http://puu.sh/dc1YU/fa1e0f3a6e.png [Broken]

    Hey so if we have a trajectory like this, where would it be maximum speed?

    From what I understand, at the midpoint, v = 0 right? So would the maximum speed be in between the bottom (initial) and the centre of the trajectory (peak), represented by B in this photo.

    I haven't done questions related to these in a while so I was just curious to know if I remember this or not.

    Thanks :)
    Last edited by a moderator: May 7, 2017
  2. jcsd
  3. Nov 30, 2014 #2


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    Use the template and check with the relevant equations under 2.
  4. Nov 30, 2014 #3
    Too useful
  5. Dec 1, 2014 #4


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    What do you expect ? You give no clue you know about energy conservation, projectile trajectory equations, or anything else related.

    At C, the thing is clearly moving to the right, so: No, v is not 0.
    If the speed would be at a maximum at B, that would mean acceleration 0 at that point. There is no argument for that, so: No, it's not in between.

    You're welcome.
  6. Dec 6, 2014 #5
    Hey, sorry about that, it was just a random question I found haha. I figured it out though, thanks :)
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