Trajectory (Quick Question) -- where would it be maximum speed?

[oldspice1212]

http://puu.sh/dc1YU/fa1e0f3a6e.png

Hey so if we have a trajectory like this, where would it be maximum speed?

From what I understand, at the midpoint, v = 0 right? So would the maximum speed be in between the bottom (initial) and the centre of the trajectory (peak), represented by B in this photo.

I haven't done questions related to these in a while so I was just curious to know if I remember this or not.

Thanks :)

 

[BvU]

Use the template and check with the relevant equations under 2.

 

[oldspice1212]

Too useful

 

[BvU]

What do you expect ? You give no clue you know about energy conservation, projectile trajectory equations, or anything else related.

At C, the thing is clearly moving to the right, so: No, v is not 0.
If the speed would be at a maximum at B, that would mean acceleration 0 at that point. There is no argument for that, so: No, it's not in between.

You're welcome.

 

[oldspice1212]

Hey, sorry about that, it was just a random question I found haha. I figured it out though, thanks :)