Transcendental Retarding Force

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SUMMARY

The discussion focuses on solving the motion of a boat experiencing a retarding force defined by F = -αe^βv, where α and β are constants. The user attempts to derive the velocity function v(t) using a perturbative approach in Mathcad and integration techniques, ultimately arriving at the equation v(t) = ln((A*B/m)*(t+constant))/-B. The user notes that increasing the initial velocity v0 results in a slower speed after a set time, which is clarified by the requirement that β must be negative to maintain positive velocity.

PREREQUISITES
  • Understanding of Newton's second law (F=ma)
  • Familiarity with differential equations and separable ODEs
  • Knowledge of exponential functions and their properties
  • Proficiency in using Mathcad for mathematical modeling
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  • Explore advanced techniques for solving separable ordinary differential equations (ODEs)
  • Learn about perturbation methods in differential equations
  • Investigate the implications of retarding forces in physics
  • Study the behavior of exponential decay functions in motion analysis
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This discussion is beneficial for physics students, engineers, and anyone involved in dynamics and motion analysis, particularly those interested in modeling forces and velocities in systems experiencing retarding forces.

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Homework Statement


A boat with initial speed v[o] is launched, and experiences a retarding force of F = -ae^Bv, where a=alpha=constant and b=beta=constant

Find v(t)
Find Time and Distance for the boat to stop


Homework Equations


F=ma


The Attempt at a Solution


the second part for tmie and distance, I am attempting to solve using mathcad with a perturbative approach incrementing vt o find dv/dt, reinserting v-dv/dt until dv/dt approaches closely to zero. This makes sense, however, only with known values for alpha and beta. I can't really think of a way to formulate v(t).
 
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I retried the problem, and was able to do some integration by treating it as a differentials and deriving a seperable ODE. However, my answers seem very odd. Here's what I did.

m*dv/dt = -[tex]\alpha[/tex]*e^[tex]\beta[/tex]*v

dv[tex]/[/tex]e^[tex]\beta[/tex]*v = -[tex]\alpha[/tex]*dt[tex]/[/tex]m

letting u = e^-Bv
du = -B*e^-Bv

[tex]\int[/tex]1/-B * du = [tex]\int[/tex]-A/m dt

going through all the integration...

we get

v(t)=ln((A*B/m)*(t+constant))/-B

with v(0) = v0


constant = (m/a*B)*e^-Bv0


so... let && = A*B/m

v(t) = ln(&&*t + e^(-B*v0))/-b


which is weird to me, because the higher we set the initial velocity, the slower the speed is after a set t. Someone help!
 
It isn't weird, because [tex]\beta[/tex] must be negative, or else the boat would move with negative velocity! :smile:
 

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