Transfer function algebraic manipulation

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Homework Help Overview

The discussion revolves around the algebraic manipulation of a transfer function, specifically the expression \( g_{p} = \frac {-1.43}{(s-1.399)(s+5.086)} \). Participants are attempting to factor and rearrange the terms to achieve a desired form.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants are exploring the factoring of the denominator and expressing constants in a different form. There is uncertainty about the validity of their manipulations and concerns regarding the implications of negative constants on stability.

Discussion Status

Some participants have provided feedback on the algebraic steps taken, indicating that while the manipulations are on the right track, there may be misunderstandings regarding the constants involved. The conversation is ongoing with no explicit consensus reached.

Contextual Notes

There is mention of a potential issue with negative time constants and their implications for system stability, which is a point of contention in the discussion. Participants express a lack of confidence in their algebraic skills, which may affect their ability to progress.

gfd43tg
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Homework Statement


upload_2015-11-7_14-2-6.png


Homework Equations

The Attempt at a Solution


I don't know if I am just stupid, but I can't see how to make this manipulation. I tried factoring the denominator

$$ g_{p} = \frac {-1.43}{(s-1.399)(s+5.086)} $$
Then take out -1.399 and 5.086
$$ g_{p} = \frac {-1.43}{-1.399(\frac {-1}{1.399}s + 1)5.086(\frac {1}{5.086}s+1)} $$
But I know this won't work, and I am not clever enough right now to come up with the right way to manipulate this thing.
 
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Maylis said:

Homework Statement


View attachment 91494

Homework Equations

The Attempt at a Solution


I don't know if I am just stupid, but I can't see how to make this manipulation. I tried factoring the denominator

$$ g_{p} = \frac {-1.43}{(s-1.399)(s+5.086)} $$
Then take out -1.399 and 5.086
$$ g_{p} = \frac {-1.43}{-1.399(\frac {-1}{1.399}s + 1)5.086(\frac {1}{5.086}s+1)} $$
But I know this won't work, and I am not clever enough right now to come up with the right way to manipulate this thing.

Your manipulations are correct; it is just that one of your constants ##\tau_i## is negative. If that is not allowed, there must be something wrong with the original ##g_p(s)##.
 
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The negative time constant is allowed, which is what makes it unstable. My algebra is weak, so for some reason I had it in my head that if I multiplied my result out, I would come up with something different from the original transfer function!
 
Maylis said:

Homework Statement


View attachment 91494

Homework Equations

The Attempt at a Solution


I don't know if I am just stupid, but I can't see how to make this manipulation. I tried factoring the denominator

$$ g_{p} = \frac {-1.43}{(s-1.399)(s+5.086)} $$
Then take out -1.399 and 5.086
$$ g_{p} = \frac {-1.43}{-1.399(\frac {-1}{1.399}s + 1)5.086(\frac {1}{5.086}s+1)} $$
But I know this won't work, and I am not clever enough right now to come up with the right way to manipulate this thing.
You've almost got the form of gp(s) that is specified, you just need to combine all the constants in the numerator and the denominator.

Hint: kp ≠ -1.43 in the final form.
 

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