Transfer function for a low pass filter

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The discussion revolves around finding the output expression (V_out) for a first-order low-pass filter with a specified transfer function and input signal. The transfer function is defined as H(f) = 1/(1+j*(f/f_B)), where the half-power frequency (f_B) is 200 Hz. The input signal includes a DC component and two sinusoidal components at different frequencies. Participants clarify that the DC component (3) remains unaffected by the filter since it corresponds to zero frequency, while the sinusoidal components are processed according to the transfer function. The key takeaway is that the DC component should be left alone in the final expression for V_out.
cseanm
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Homework Statement



The input signal of a first-order lowpass filter with a transfer function given by eqn 1 below and a half power frequency of 200 Hz is eqn 2 below. Find an expression for V_out

Homework Equations



eqn1:
H(f) = 1/(1+j*(f/f_B) where f is the frequency and f_B is the half-power frequency
eqn2:
v_in (t) = 3 + 2sin(800*PI*t + 30) + 5cos(20000*PI*t)

v_out/v_in = H(f)

The Attempt at a Solution



I have already gotten that v_in = 3 + 2cos(800*PI*t - 60) + 5cos(20000*PI*t)
then I would multiply each component by H(f) which will give me:
H(400) = 1/sqrt(5) phase(-arctan(2))
H(1000) = 1/sqrt(26) phase(-arctan(5))

v_out = 3*H(?) + 2 phase(-60)*H(400) + 5 phase(0)*H(1000)

pretty much I just do not know what I do about the 3. Do I simply leave it alone?

Thanks!
 
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cseanm said:
pretty much I just do not know what I do about the 3. Do I simply leave it alone?

It's a DC component, frequency is zero. What does your transfer function do to a signal with zero frequency?
 
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