Transfer function, Laplace Transform

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SUMMARY

The discussion focuses on finding the transfer function V2(s)/V1(s) in the Laplace transform domain for a circuit involving a resistor and capacitor. The initial attempt yielded an incorrect expression due to a sign error. The correct transfer function is derived as V2/V1 = (1 + sRC)/(2 + sRC), where R is the resistance and C is the capacitance. This highlights the importance of careful algebraic manipulation in circuit analysis.

PREREQUISITES
  • Understanding of Laplace transforms and their application in circuit analysis.
  • Knowledge of KCL (Kirchhoff's Current Law) and its use in electrical circuits.
  • Familiarity with capacitor equations and impedance in the s-domain.
  • Basic algebraic manipulation skills for solving transfer functions.
NEXT STEPS
  • Study the derivation of transfer functions using the Laplace transform in electrical circuits.
  • Learn about impedance calculations for resistors and capacitors in the s-domain.
  • Explore examples of voltage dividers and their applications in circuit design.
  • Review common mistakes in Laplace transform applications to avoid sign errors.
USEFUL FOR

Electrical engineering students, circuit designers, and anyone involved in analyzing and designing circuits using Laplace transforms.

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Homework Statement



[PLAIN]http://img340.imageshack.us/img340/8508/circuit.png

Find V2(s)/V1(s) (Laplace transform domain)

Homework Equations


KCL, capacitor equation.

The Attempt at a Solution


[tex]\frac {-V_2}{R} + \frac {V_1-V_2}{R} + C \frac {d(V_1-V_2)}{dt}=0[/tex]
But in Laplace domain it follows that
[tex]\frac {V_2 (s)}{V_1 (s)} = \frac {sRC+1}{sRC}[/tex]
and that is apparently incorrect.
Any thoughts on what I did wrong, and what I should do?

Thanks in advance
 
Last edited by a moderator:
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It's a voltage divider. Let z be the impedance of the resistor-capacitor parallel pair. Then

v2/v1 = R/(R + z)

But z = (R * 1/sC)/(R + 1/sC) = R/(1 + sRC)

Therefore,

v2/v1 = (1 + sRC)/(2 + sRC)
 
Sorry, I was actually correct. Forgot about a minus sign in one place. Anyway, thanks for the answer. At least I know that now I have the correct answer.
Cheers.
 

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