Transformation of vector components

In summary, the components of a vector ##v## in two coordinate systems, ##x## and ##x'##, are related via ##v'^\mu = \frac{\partial x'^\mu}{\partial x^\sigma}v^\sigma##. When evaluating this at a specific ##x'(x_0) \equiv x'_0##, there is no difference in evaluating ##v'^\mu(x'_0) = \frac{\partial x'^\mu}{\partial x^\sigma}(x_0)v^\sigma(x_0)## or ##v'^\mu(x'_0) = (\frac{\partial x'^\mu}{\partial x^\sigma}v^\sigma)(x_0
  • #1
kent davidge
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The components of a vector ##v## are related in two coordinate systems via ##v'^\mu = \frac{\partial x'^\mu}{\partial x^\sigma}v^\sigma##. When evaluating this at a specific ##x'(x_0) \equiv x'_0##, how should we proceed? ##v'^\mu(x'_0) = \frac{\partial x'^\mu}{\partial x^\sigma}(x_0)v^\sigma(x_0)## or ##v'^\mu(x'_0) = (\frac{\partial x'^\mu}{\partial x^\sigma}v^\sigma)(x_0)##?

That is, should we first work out the sum of the functions and then evaluate the product? Or can we evaluate each separately?
 
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  • #2
I do not see difference. Do they differ ?
 
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  • #3
anuttarasammyak said:
I do not see difference. Do they differ ?
Not in general, I think. However you might get into trouble if the Jacobian ##\frac{\partial x'^\mu}{\partial x^\nu}## or the components ##v^\sigma## have some weird behaviour at ##x_0##, but so that yet their combination is a function that is fine there.
 
  • #4
I interpret the two,
[tex]F(x_0)G(x_o)=[F(x)G(x)]_{x=x_0}[/tex]
The both share weirdness if any.
 
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