Transformation relations tensors

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SUMMARY

The discussion focuses on the derivation of 2D stress transformation relations using directional cosines and transformation equations. The key equations presented are: σ_{xx}^{'} = σ_{xx} cos²θ + σ_{yy} sin²θ + 2σ_{xy} cos θ sin θ, σ_{yy}^{'} = σ_{xx} sin²θ + σ_{yy} cos²θ - 2σ_{xy} cos θ sin θ, and σ_{xy}^{'} = σ_{xx}(cos²θ - sin²θ) + (σ_{yy} - σ_{xx}) sin θ cos θ. The transformation equation σ_{ij}^{'} = m_{ip} m_{jp} σ_{pq} is also highlighted, along with the 2D directional cosine matrix m_{ij} = [cos θ, -sin θ; sin θ, cos θ]. The confusion regarding the σ_{pq} matrix elements is clarified as being equivalent to the original stress matrix elements.

PREREQUISITES
  • Understanding of 2D stress analysis
  • Familiarity with transformation equations in mechanics
  • Knowledge of directional cosines
  • Basic matrix operations
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  • Study the derivation of 2D stress transformation relations in mechanics
  • Learn about the application of directional cosines in stress analysis
  • Explore matrix representation of stress tensors
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Mechanical engineers, civil engineers, and students studying solid mechanics who need to understand stress transformation in 2D systems.

roldy
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I'm trying to understand the transformation relations for 2d stress and the book doesn't show the derivation of the 2d stress transformation relations from the directional cosines. The 2d stress transformation relations are found by using the transformation equation and the 2d directional cosines matrix. I'm really confused as to how they go about performing the math.

2d stress transformation relations:

\sigma_{xx}^{'}= \sigma_{xx} \cos^2 \theta + \sigma_{yy} \sin^2 \theta + 2\sigma_{xy} \cos \theta \sin \theta

\sigma_{yy}^{'}= \sigma_{xx} \sin^2 \theta + \sigma_{yy} \cos^2 \theta - 2\sigma_{xy} \cos \theta \sin \theta

\sigma_{xy}^{'}= \sigma_{xx}(\cos^2 \theta - sin^2 \theta) + (\sigma_{yy} - \sigma_{xx}) \sin \theta \cos \theta

transformation equation:

\sigma_{ij}^{'} = m_{ip} m_{jp} \sigma_{pq}

2d directional cosine matrix:

m_{ij} = \left[\stackrel{\cos \theta}{ -\sin \theta}\ \stackrel{\sin \theta}{\cos \theta} \right]

I guess the thing that I'm confused about is \sigma_{pq}. What does that matrix look like?
 
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roldy said:
I'm trying to understand the transformation relations for 2d stress and the book doesn't show the derivation of the 2d stress transformation relations from the directional cosines. The 2d stress transformation relations are found by using the transformation equation and the 2d directional cosines matrix. I'm really confused as to how they go about performing the math.

2d stress transformation relations:

\sigma_{xx}^{'}= \sigma_{xx} \cos^2 \theta + \sigma_{yy} \sin^2 \theta + 2\sigma_{xy} \cos \theta \sin \theta

\sigma_{yy}^{'}= \sigma_{xx} \sin^2 \theta + \sigma_{yy} \cos^2 \theta - 2\sigma_{xy} \cos \theta \sin \theta

\sigma_{xy}^{'}= \sigma_{xx}(\cos^2 \theta - sin^2 \theta) + (\sigma_{yy} - \sigma_{xx}) \sin \theta \cos \theta

transformation equation:

\sigma_{ij}^{'} = m_{ip} m_{jp} \sigma_{pq}

2d directional cosine matrix:

m_{ij} = \left[\stackrel{\cos \theta}{ -\sin \theta}\ \stackrel{\sin \theta}{\cos \theta} \right]

I guess the thing that I'm confused about is \sigma_{pq}. What does that matrix look like?

I suspect σpq is simply the original matrix elements.
σ11 = σxx etc.

\sigma_{ij}^{'} = m_{ip} m_{jp} \sigma_{pq}
should be
\sigma_{ij}^{'} = m_{ip} m_{jq} \sigma_{pq}
 
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