Transition metal oxidation states

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SUMMARY

Nickel (Ni) predominantly forms NiO with an oxidation state of +2, unlike other transition metals that exhibit a broader range of oxidation states. This behavior is similar to that of zinc (Zn) and copper (Cu), which are located adjacent to nickel in the periodic table. The underlying reason is the poor shielding effect of d-electrons from the nuclear charge, leading to an increase in effective nuclear charge as the number of d-electrons rises. Consequently, the energy of d-electrons decreases relative to valence s-electrons, limiting their participation in bonding as one moves across the period.

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  • Understanding of transition metal chemistry
  • Familiarity with oxidation states and their implications
  • Knowledge of d-electron configurations
  • Basic grasp of Slater's rules for effective nuclear charge
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  • Research the oxidation states of transition metals in various compounds
  • Study Slater's rules in detail to understand effective nuclear charge
  • Explore the bonding characteristics of d-block elements
  • Investigate the similarities and differences between nickel, zinc, and copper in terms of oxidation states
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Moogie
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Hi

Why does Ni only form NiO with oxidation state of +2 whereas the other transition metals form a wide range of oxides with variable oxidation states

Thanks
 
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It behaves the same way as do Zn and Copper which are its neighbours.
The reason is that the d-electrons shield each other only badly from the nuclear charge. Hence the effective nuclear charge increases (Google for Slater rules) when the number of d-electrons increases and the energy of the d-electrons relative to the valence s-electrons drops when going in the period from left to right so that they participate no longer in bonding at the end of the period.
 

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