Transition probability from two states

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SUMMARY

The discussion focuses on calculating the transition probability from state |1⟩ to state |2⟩ in a quantum system represented by a Hamiltonian matrix $$\begin{pmatrix} E&U\\U&E \end{pmatrix}$$. The derived formula for the transition probability over a time interval t is given by $$p(t) = \sin^2(Ut/\hbar)$$. Participants clarified that the eigenstates |u1⟩ and |u2⟩ can be used to express the states |1⟩ and |2⟩, and that the first-order perturbation theory aligns with the exact result obtained. The approximation holds true under the condition that the first-order transition probability remains normalized.

PREREQUISITES
  • Understanding of quantum mechanics, specifically the time-dependent Schrödinger equation.
  • Familiarity with Hamiltonian mechanics and matrix representations of quantum states.
  • Knowledge of eigenstates and eigenvalues in quantum systems.
  • Basic concepts of perturbation theory in quantum mechanics.
NEXT STEPS
  • Study the derivation of the time-dependent Schrödinger equation in quantum mechanics.
  • Learn about Hamiltonian matrices and their role in quantum state evolution.
  • Explore perturbation theory and its applications in calculating transition probabilities.
  • Investigate the significance of eigenstates and eigenvalues in quantum mechanics.
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Quantum physicists, graduate students in physics, and researchers focusing on quantum mechanics and transition probabilities will benefit from this discussion.

CAF123
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Homework Statement


A system has two independent states ##|1\rangle## and ##|2\rangle## represented by column matrices ##|1\rangle \rightarrow (1,0)## and ##|2\rangle \rightarrow (0.1)##. With respect to these two states, the Hamiltonian has a time independent matrix representation $$\begin{pmatrix} E&U\\U&E \end{pmatrix},$$ E and U both real. Show that the probability of a transition from state ##|1\rangle## to state ##|2\rangle## in a time interval ##t## is given by (without any approximation) ##p(t) = \sin^2(Ut/\hbar)##

Homework Equations


[/B]
Time dependent Schrödinger equation

The Attempt at a Solution


[/B]
Reexpress the states in terms of energy eigenstates, so can write the general evolution of an arbritary state. The eigenvectors of the Hamiltonian are ##\frac{1}{\sqrt{2}}(1,1) = |u_1\rangle## and ##\frac{1}{\sqrt{2}}(1,-1) = |u_2\rangle##. Then ##|1\rangle = \frac{1}{\sqrt{2}}(|u_1\rangle + |u_2 \rangle )## while ##|2\rangle = \frac{1}{\sqrt{2}}(|u_1\rangle - |u_2 \rangle ).## So generic state is $$|\Psi,t_o \rangle = C_1 (1,0) + C_2 (0,1) \Rightarrow |\Psi, t\rangle = \frac{C_1}{\sqrt{2}} (|u_1\rangle e^{-iE_1 t/\hbar} + |u_2 \rangle e^{-iE_2 t/\hbar} ) + \frac{C_2}{\sqrt{2}} (|u_1\rangle e^{-iE_1 t/\hbar} - |u_2 \rangle e^{-iE_2 t/\hbar}).$$ But I am not sure how to progress. I am looking to compute ##\langle \Psi, t | 1 \rangle## and from that extract the probability of finding state |2>.
Thanks!
 
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You don't need to write a generic state. The problem asks about a transition from 1 to 2.
All you need to do is write (as you have already done) 1 and 2 in the eigenvector basis. Then evolve 1 in time t and project it into 2, to find the probability of finding 2.
 
Hi assed,
assed said:
You don't need to write a generic state. The problem asks about a transition from 1 to 2.
All you need to do is write (as you have already done) 1 and 2 in the eigenvector basis. Then evolve 1 in time t and project it into 2, to find the probability of finding 2.
Thanks, I see. I noticed that the result obtained from the first order time dependent theory gives exactly the same result. So the first order correction to the transition probability induced by the given time independent hamiltonian is exact. Is there any reason why we would expect this or does this imply that the approximation is true regardless of size of U? Thanks!
 
Woops, ignore my last reply, the first order term coming from perturbation theory gives the first term in the expansion of sin^2 Ut/h, which is more sensible. So the approximation is valid for a time interval ##t## such that ##P^{(1)}(t) = P_{1 \rightarrow 2} + P_{1 \rightarrow 1} = 1## holds. Is that correct?
 

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