How Do You Calculate Capacitance and Inductance in a Transmission Line Model?

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SUMMARY

The discussion focuses on calculating the capacitance per unit length (C) and inductance per unit length (L) of a transmission line model consisting of a cylindrical conductor and a conducting plane. The user derived the equations for capacitance and inductance using electrostatic principles and Ampere's law. The derived formulas are C = (1/2πrε₀)ln[(d-r)/r] + (1/2ε₀)(d-r)/m and L = (μ/2π)ln[(d-r)/r] + μ(d-r)/m, where ε₀ is the permittivity of free space and μ is the permeability of free space. The user also verified the relationship 1/√(LC) = c, confirming the consistency of the derived values.

PREREQUISITES
  • Understanding of electrostatics and electric fields
  • Familiarity with Ampere's law and magnetic fields
  • Knowledge of logarithmic functions in physics
  • Basic concepts of transmission line theory
NEXT STEPS
  • Study the application of image theory in electrostatics
  • Learn about the derivation of capacitance and inductance in different transmission line configurations
  • Explore the relationship between capacitance, inductance, and wave propagation speed in transmission lines
  • Investigate the effects of non-uniform charge distribution on capacitance calculations
USEFUL FOR

Electrical engineers, physics students, and professionals involved in transmission line modeling and analysis will benefit from this discussion.

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Homework Statement


A transmission line consists of a cylindrical conductor of radius r at a distance d in air from a conducting plane (r >>d).

Derive the capacitance per unit length C and the inductance per unit length L and
check that 1/sqrt(LC) = c.


Homework Equations





The Attempt at a Solution


I thought I could just give the cyclinder a charge -Q and the plane a charge +Q and superimpose the fields. So that along the line through the centre of the cylinder and normal to the plane, the field is:

E = -Q/(2.pi.r.l.e0) -Q/(2.l.m.e0)

Where l is the length of the cylinder and l, m are the dimensions of the plane.

Then integrating to find the potential difference and dividing by Q and multiplying by l gives:

1/C = (1/2.pi.r.e0)*ln[(d-r)/r] + (1/2e0)*(d-r)/m

Then the B due to the cylinder would be vI/2.pi.r where I am using v as permeability of free space. And on the normal through the centre line, it would be perpendicular to the line.

I think that on the line, the field from all the elements on the plane would superimpose to produce a field perpendicular to the line, which Ampere would then give as vI/m

So

B = vI/2.pi.r + vI/m

Then flux is the integral of that, and dividing by I and l gives L:

L = (v/2.pi)*ln[(d-r)/r] + v(d-r)/m

But this doesn't seem right.

Any help? Thanks.
 
Physics news on Phys.org
You can't assume that the charge on the plane would be uniformly distributed. However, since it is an infinite plane, you can use image theory to model the effective charge distribution.
 

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