Transmission Line Reflected Waves

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SUMMARY

The discussion focuses on the behavior of waves in transmission lines, specifically addressing the conditions of short circuits and their impact on wave reflection. It confirms that with a short circuit, the reflection coefficient is -1, resulting in a phase shift of 180 degrees. The interaction between incident and reflected waves leads to the formation of standing waves, which do not cancel each other out completely but create varying amplitudes along the line. The mathematical representation of these waves is crucial for understanding their behavior.

PREREQUISITES
  • Understanding of transmission line theory
  • Familiarity with wave mechanics
  • Basic knowledge of trigonometric identities
  • Ability to visualize wave interactions
NEXT STEPS
  • Study the mathematical derivation of standing waves in transmission lines
  • Learn about the implications of different reflection coefficients
  • Explore the concept of impedance matching in transmission lines
  • Investigate the effects of open and short circuits on wave propagation
USEFUL FOR

Electrical engineers, physics students, and professionals involved in telecommunications or signal processing who seek to deepen their understanding of wave behavior in transmission lines.

jendrix
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Hi ,

I'm studying transmission lines and how waves move through the device , so far I haven't delved into the maths behind it as I have been trying to get an overview of it.So far I have seen the effects when there is an open circuit , shorted and matched impedance loads.

The example I saw said that with a short circuit :

Reflection coefficient =-1

Phase 180 Degrees

It then says how the incident and reflected waves will interfere to create a standing wave. Is this correct? I thought that if the incident wave and reflected wave (which will be in anti-phase) combined it would be destructively giving no resultant wave?

Thanks
 
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Imagine the two waves as they travel opposite each other; one incident and one reflected. This would bring about a different sum of the amplitudes at different times and at different locations along the line. Two sine waves running in opposite directions; neither would they cancel everywhere, nor would they add up to higher values everywhere. Whether the reflection coefficient is -1 or +1 it doesn't really matter. Both will yield standing waves, though with different null-locations.
 
jendrix said:
The example I saw said that with a short circuit :

Reflection coefficient =-1

Phase 180 Degrees

It then says how the incident and reflected waves will interfere to create a standing wave. Is this correct? I thought that if the incident wave and reflected wave (which will be in anti-phase) combined it would be destructively giving no resultant wave?

Thanks
Yes, it is correct, as Dorian Black indicated. For me it is hard to visualize the sum of two waves traveling in opposite directions. I actually think the math helps here. Let the short circuit be at ##x=0##. If the incident wave is traveling in the positive x direction, then a simple voltage wave can be written as ##v_i = v_0cos(\omega t - k x) ##. The reflected wave is then ##v_r= -v_0cos(\omega t + k x) ##. The total voltage is then ## v = v_r + v_i##. If you use trig identities you can turn this into the standing wave pattern you are looking for.

jason
 
Last edited:

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