- #1

- 2

- 0

We have 2 boundary conditions at the step at x = x0:

Y1(x0) = Y2(x0)

1/m1*d/dxY1(x0) = 1/m2*d/dxY2(x0)

Note that the second boundary condition is not the standard one, since we have to account for the different masses, in order to have current conservation.

**When plotting T(E) it only approaches unity for increasing E, if the masses are equal. If they are not equal T(E) approaches a value less than unity.**

I'm just wondering if this result is correct? Is there always some reflection at a heterojunction with different effective electron masses, even for very large energies?

Thanks,

John