Transmission probability of a massive particle

Click For Summary
SUMMARY

The discussion focuses on calculating the transmission probability of a massive particle encountering a potential defined by V=V_0 d[\delta(x-a)+\delta(x+a)]. The wave functions for three regions are established: region 1 (x < -a), region 2 (-a < x < a), and region 3 (x > a). The continuity conditions at x = -a and x = a lead to a system of equations involving reflection (R), transmission (T), and coefficients (A, B). To solve for these coefficients, one must apply the Schrödinger equation's derivative conditions at the delta function locations.

PREREQUISITES
  • Understanding of Schrödinger's Equation
  • Familiarity with delta function potentials
  • Knowledge of wave function continuity and boundary conditions
  • Basic concepts of quantum mechanics, particularly wave-particle duality
NEXT STEPS
  • Study the application of delta function potentials in quantum mechanics
  • Learn how to derive boundary conditions from Schrödinger's Equation
  • Explore the concept of transmission and reflection coefficients in quantum tunneling
  • Investigate the behavior of wave functions in potential barriers and wells
USEFUL FOR

Students and professionals in quantum mechanics, particularly those studying wave-particle interactions and potential barriers. This discussion is beneficial for anyone looking to deepen their understanding of transmission probabilities in quantum systems.

mnky9800n
Messages
4
Reaction score
0

Homework Statement


Consider the potential V=V_0 d[\delta(x-a)+\delta(x-a)]. Find the transmission probability of the potential for a particle of mass m and wave number \sqrt{\frac{2mE}{\hbar^2}} incident on the potential. Discuss the behavior when ka~\pi/2.

Homework Equations


Schrödinger's Equation
H\psi=E\psi

The Attempt at a Solution



The solutions to SE for each region are as follows:
region 1: a < x
\psi_1 = e^{ikx}+Re^{-ikx}
region 2: -a < x < a
\psi_2 = Ae^{ikx}+Be^{ikx}
region 3: a < x
\psi_3 = Te^{ikx}

Because the \delta-function means the wave function is continuous but the derivative is not at x = a we can say:

\psi_1(-a) = \psi_2(-a)
\psi_2(a) = \psi_3(a)

therefore:

1+Re^{2ika} = A+Be^{2ika}
A+Be^{-2ika} = T

This is where I get stuck. I have no idea where to go from here.
 
Last edited:
Physics news on Phys.org
You have 4 unknowns, so you need two more equations to be able to solve for them. Those equations come from considering the derivatives of the wave functions. Integrate the Schrödinger equation between a-ε and a+ε. In the limit as ε→0, you'll get a relationship between the derivatives on the two sides of the delta function. Do the same thing around x=-a. Then you should be in a position to solve for the coefficients.

I'd go into more detail, but I don't have time right now. It's probably done in your book somewhere, or someone else may come by to provide more help if you can't figure it out.
 

Similar threads

  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
Replies
16
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K
Replies
7
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K