Transpose a matrix whose elements are themselves matrices

Click For Summary
The discussion revolves around the correct interpretation of the transpose of a matrix composed of matrices, specifically when dealing with matrices A and B. It highlights two interpretations: one where (A B) is viewed as a 2x4 matrix formed by concatenating A and B, leading to the transpose being represented as (AT BT), and another where it is seen as a 1x2 matrix of 2x2 matrices, resulting in the transpose being (A B). The importance of understanding the dimensions of the matrices involved is emphasized, as it affects how the transpose is computed. The conversation clarifies that the standard definition of transpose does not require transposing the elements within the matrices themselves. Ultimately, the preferred interpretation is that which allows for a more useful application of the transpose operation.
robotsheep
Messages
10
Reaction score
0
If I have (for simplicity) a vector ( A, B) where A and B are matrices how does the transpose of this look, is it ( AT, BT) or

(AT
BT)
 
Physics news on Phys.org
Think about what the dimension should be.
 
or

(A
B)
 
Robert1986 said:
Think about what the dimension should be.

Sorry, I don't really understand what you mean by "dimension" in this case;

I know that the transpose of a 1x2 matrix should be a 2x1 matrix but I don't know whether the elements actually inside the matrix should be transposed once I make the matrix a 2x1.

Thank you in advance for any help.
 
From wikipedia:
In linear algebra, the transpose of a matrix A is another matrix AT (also written A′, Atr or At) created by anyone of the following equivalent actions:
reflect A over its main diagonal (which runs top-left to bottom-right) to obtain AT
write the rows of A as the columns of AT
write the columns of A as the rows of AT

It doesn't say that anything should be done to the elements of the matrix so I guess it would be just
A
B
(columns of A written as rows)
 
robotsheep said:
Sorry, I don't really understand what you mean by "dimension" in this case;
He meant that you should think about the number of rows and columns. However, this only helps is you interpret the notation in the first of the two ways I'm describing below.

robotsheep said:
I know that the transpose of a 1x2 matrix should be a 2x1 matrix but I don't know whether the elements actually inside the matrix should be transposed once I make the matrix a 2x1.
If A and B are 2×2 matrices for example, then I would interpret a notation like (A B) not as a 1×2 matrix whose elements are are 2×2 matrices, but as a 2×4 matrix whose 11, 12, 21 and 22 elements are respectively the 11, 12, 21, 22 elements of A, and whose 13, 14, 23, 24 elements are respectively the 11, 12, 21, 22 elements of B. With this interpretation of the notation, it's obvious that the transpose of (A B) is
$$\begin{pmatrix}A^T\\ B^T\end{pmatrix}.$$ If you instead interpret it as a 1×2 matrix whose elements are are 2×2 matrices, then the standard definition of "transpose" would of course just give you
$$\begin{pmatrix}A\\ B\end{pmatrix}.$$ I think the former interpretation is far more useful, and I assume that to some authors, this is a reason to use a different definition of "transpose", so that you can think of (A B) as a 1×2 matrix, and still have its transpose be
$$\begin{pmatrix}A^T\\ B^T\end{pmatrix}.$$ I don't see any reason to use a definition that makes ##\begin{pmatrix}A & B\end{pmatrix}^T=\begin{pmatrix}A^T & B^T\end{pmatrix}##.
 
Last edited:
Fredrik said:
He meant that you should think about the number of rows and columns. However, this only helps is you interpret the notation in the first of the two ways I'm describing below.


If A and B are 2×2 matrices for example, then I would interpret a notation like (A B) not as a 1×2 matrix whose elements are are 2×2 matrices, but as a 2×4 matrix whose 11, 12, 21 and 22 elements are respectively the 11, 12, 21, 22 elements of A, and whose 13, 14, 23, 24 elements are respectively the 11, 12, 21, 22 elements of B. With this interpretation of the notation, it's obvious that the transpose of (A B) is
$$\begin{pmatrix}A^T\\ B^T\end{pmatrix}.$$ If you instead interpret it as a 1×2 matrix whose elements are are 2×2 matrices, then the standard definition of "transpose" would of course just give you
$$\begin{pmatrix}A\\ B\end{pmatrix}.$$ I think the former interpretation is far more useful, and I assume that to some authors, this is a reason to use a different definition of "transpose", so that you can think of (A B) as a 1×2 matrix, and still have its transpose be
$$\begin{pmatrix}A^T\\ B^T\end{pmatrix}.$$ I don't see any reason to use a definition that makes ##\begin{pmatrix}A & B\end{pmatrix}^T=\begin{pmatrix}A^T & B^T\end{pmatrix}##.

Thank you, this really cleared it up for me.
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 14 ·
Replies
14
Views
4K