Transverse Speed of a particle on a wave

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The equation of the transverse wave is y = 6.0sin(0.012pi*x + 4.9pi*t), and the goal is to find the maximum transverse speed of a particle in the string. The initial approach involved calculating the derivative of the displacement with respect to position, yielding y' = 6*0.012pi*cos(0.012pi*x). However, the correct method requires taking the time derivative of the displacement equation. The maximum transverse speed is determined by evaluating the time derivative, which was not initially considered. Thus, the correct approach involves finding the derivative with respect to time to obtain the maximum speed.
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Homework Statement


The equation of a transverse wave traveling along a very long string is given by y = 6.0sin(0.012pi*x + 4.9pi*t), where x and y are expressed in centimeters and t is in seconds.

Find the maximum transverse speed of a particle in the string.


Homework Equations





The Attempt at a Solution


I want the speed, or rate of change of position, or derivative of position. The given equation represents the transverse displacement, so, at t = 0, I would have y' = 6*0.012picos(0.012pi*x). Since y(x, t) is a sine function, the greatest slope would be at (0, 0), so y'(0, 0) would represent the greatest rate of change of y(x, t).

So the maximum transverse speed of a particle in the string would be 6*0.012*pi, correct?

This, however, is not the right answer, so why not?
 
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You have to take the derivative with respect to time.
 
The speed is the time derivative.
 
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