Transverse Speed of a particle on a wave

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SUMMARY

The maximum transverse speed of a particle on a wave described by the equation y = 6.0sin(0.012πx + 4.9πt) is determined by taking the time derivative of the transverse displacement. The initial calculation of the speed at t = 0 yields y' = 6 * 0.012πcos(0.012πx), but this only represents the spatial derivative. The correct approach requires calculating the time derivative, leading to the conclusion that the maximum transverse speed is derived from the full time-dependent wave equation.

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  • Understanding of wave equations and their properties
  • Knowledge of calculus, specifically derivatives
  • Familiarity with trigonometric functions and their derivatives
  • Basic physics concepts related to wave motion
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  • Study the concept of wave speed and its relation to frequency and wavelength
  • Learn how to compute derivatives of trigonometric functions in the context of wave equations
  • Explore the relationship between transverse speed and wave parameters
  • Investigate the effects of different waveforms on particle motion
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Students in physics or engineering, particularly those studying wave mechanics, as well as educators looking for examples of wave motion and calculus applications.

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Homework Statement


The equation of a transverse wave traveling along a very long string is given by y = 6.0sin(0.012pi*x + 4.9pi*t), where x and y are expressed in centimeters and t is in seconds.

Find the maximum transverse speed of a particle in the string.


Homework Equations





The Attempt at a Solution


I want the speed, or rate of change of position, or derivative of position. The given equation represents the transverse displacement, so, at t = 0, I would have y' = 6*0.012picos(0.012pi*x). Since y(x, t) is a sine function, the greatest slope would be at (0, 0), so y'(0, 0) would represent the greatest rate of change of y(x, t).

So the maximum transverse speed of a particle in the string would be 6*0.012*pi, correct?

This, however, is not the right answer, so why not?
 
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You have to take the derivative with respect to time.
 
The speed is the time derivative.
 

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