Transverse Wave: Amplitude, Wavelength, Speed & Direction

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Homework Help Overview

The discussion revolves around a transverse wave described by the equation y = 0.04 cos(2.5 x - 5 t), focusing on determining the amplitude, wavelength, speed, direction of propagation, and frequency of the wave.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss how to extract the wavelength from the given wave equation, with one suggesting to fix time to simplify the equation. There is uncertainty about the correct method to determine the wavelength and frequency.

Discussion Status

Some participants have provided guidance on how to approach the problem mathematically, particularly regarding the wave equation and its components. There is an ongoing exploration of the relationships between wavelength, frequency, and wave speed.

Contextual Notes

Participants are navigating the complexities of the wave equation and its parameters, with some confusion about units and the correct interpretation of the equation. There is a mention of using radians instead of degrees for calculations.

mattmannmf
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The transverse displacement of an harmonic wave on a stretched rope is y = 0.04 cos(2.5 x - 5 t), where x and y are in meters and t is in seconds.

a) What is the amplitude of this wave?
A = m *
.04 OK

b) What is the wavelength of this wave?

c) What is the speed with which this wave travels?

d) In what direction is this wave propagating?
+x

e) What is the frequency (NOT the angular frequency) of this wave?
f = s-1

First off i need to find the wavelength. i am not sure where to start. in terms of the equation they gave me, idk how i can use that because it has 3 variables in stead of 2 so i can't plot it to figure out the wave length.. any ideas?
 
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To get wavelength, fix t to be any constant ... use t=0 for convenience.

You now have a periodic function in x, and the "period" of that function will be the wavelength.
 
so my new equation would be:
y=.04cos(2.5x) ? i get the wavelength to be 144 (just by graphing it) which is wrong
 
mattmannmf said:
so my new equation would be:
y=.04cos(2.5x) ?
Yes, good.

i get the wavelength to be 144 (just by graphing it) which is wrong
No. Try using radians, not degrees.
 
ahh ok...2.51.

now I am kind of stuck as in velocity... no idea how to get it. equation is
v=(wavelength* frequency)
how do i determine frequency?
 
These questions are most easily approached through the pure mathematical formula of waves

The wave equation is
D(x, t) = Acos(kx-wt) for a wave traveling in the positive x direction and d(x,t) = Acos (kx+wt) for a wave traveling in the negative x direction

k is something called the wave number and is equal to 2Pi/wavelength, and w is called the angular frequency and is equal to 2pi*frequency. These are the mathematics of transverse waves.

Look at your equation of the traveling wave, and you should be able to solve for everything you need :)
 
ahhh ok..wow that made everything clear..thanks
 

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