Here is a transverse wave problem:(adsbygoogle = window.adsbygoogle || []).push({});

Consider transverse waves moving along a stretched spring fixed to an oscillator. Suppose the mass of the spring is 10 grams, its relaxed (not stretched) length is 1.00 meters, and its spring constant (if stretched) is 5.0 N/cm. The spring is tensioned via a pulley wheel and a hanging weight. The final length of the stretched spring is 1.50 meters (from the oscillator to the weight). How fast will transverse waves propogate along the stretched spring?

I am using v= square root of:(tension over mass density)

Initial mass density: 0.01 kg/1.00 m = 0.01 kg/m

Final mass density: 0.01 kg/1.50 m = 0.0067 kg/m

T = mass (weight) * gravity = x kg*9.8 m/s^2

So now to find T....

I have tried F = -kx, where mg= -kx, and T=-F. Therefore, T = (-500 N/m * 1.50 m) = 750 N, or kgm/s^2.

So... v = square root of: (750 N/0.0067 kg/m) = 334.6 m/s

I am just a little unsure. Could somebody please comment, whether right or wrong? If wrong, would you mind pointing me in the right direction? Thank you - I appreciate it very much.

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# Homework Help: Transverse Wave oscillator Problem

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