Trapezoidal Rule: Maximum error in approximation?

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The discussion centers on determining the maximum error in the trapezoidal rule approximation for the integral of a function f(x) over the interval [0, 3], given the constraints on the second derivative f''(x). The key formula for error estimation is |ET|≤ (K(b-a)^3)/(12n^2), where K represents the maximum value of |f''(x)|. Since the specific function f(x) is not provided, participants agree that one can only establish an upper bound for the absolute error based on the known limits of f''(x), which is between -2 and 1. Consequently, K can be taken as 2 for the purposes of calculating the error bound. The discussion emphasizes that while finding the exact maximum is not feasible, establishing a reasonable upper bound is sufficient for error estimation.
Jess Karakov
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Homework Statement


Suppose that T4 is used to approximate the ∫ from 0 to 3 of f(x)dx, where -2 ≤ f ''(x) ≤ 1 for all x. What is the maximum error in the approximation?

Homework Equations


|ET|≤ (K(b-a)^3)/(12n^2)

The Attempt at a Solution


So I know how to find the error of the trapezoidal rule using the above equation, but I do not understand how to find the maximum error in an approximation.
To find the max error I would find the max/mins of f ''(x), right? But I don't know how to do that when f(x) is not given
 
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Jess Karakov said:

Homework Statement


Suppose that T4 is used to approximate the ∫ from 0 to 3 of f(x)dx, where -2 ≤ f ''(x) ≤ 1 for all x. What is the maximum error in the approximation?

Homework Equations


|ET|≤ (K(b-a)^3)/(12n^2)

The Attempt at a Solution


So I know how to find the error of the trapezoidal rule using the above equation, but I do not understand how to find the maximum error in an approximation.
To find the max error I would find the max/mins of f ''(x), right? But I don't know how to do that when f(x) is not given

You can't. All you can do is find an upper bound on the absolute error, so your actual error may be a lot less than your bound. Just find an upper bound on ##|f''(x)|## over ##x \in [0,3]##.

Note: people hardly ever find best bounds by finding actual maxima of things like ##|f''(x)|##; typically, they are satisfied with decent bounds.
 
So K would just be 2?
 
Jess Karakov said:
So K would just be 2?

You tell me.
 
yes...:wink:
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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