Traveling quantum Gaussian wave packet

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SUMMARY

The discussion focuses on solving the Schrödinger equation (S.E.) for a quantum Gaussian wave packet represented by the wavefunction $$\Psi(x,0) = \sqrt{\pi_0(x)} \exp(iQx)$$. Participants emphasize the importance of using the time-dependent wavefunction $$\Psi(x,t)$$ instead of the initial condition $$\Psi(x,0)$$. Key insights include the relationship between the standard deviation $$\sigma(t)$$ and the velocity $$v$$, as well as the necessity of correctly interpreting the phase factor $$\exp(iQx)$$. The final goal is to derive the probability density $$\pi(x,t)$$ and the functional forms of $$\sigma(t)$$ and $$v$$.

PREREQUISITES
  • Understanding of the Schrödinger equation for free particles
  • Familiarity with Gaussian distributions and their properties
  • Knowledge of complex numbers and their conjugates
  • Basic proficiency in LaTeX for mathematical notation
NEXT STEPS
  • Study the derivation of the time-dependent Schrödinger equation
  • Learn about the properties of Gaussian wave packets in quantum mechanics
  • Explore the relationship between velocity $$v$$ and wave number $$Q$$ in quantum systems
  • Investigate the implications of time evolution on probability densities in quantum mechanics
USEFUL FOR

Students of quantum mechanics, physicists working with wave functions, and anyone interested in the mathematical foundations of quantum wave packets.

boudreaux
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Homework Statement
Solve the Schrodinger equation and show the probability density is as follows
Relevant Equations
The Schrodinger equation for a free particle is

$$ih(\partial \Psi/\partial t) = -\frac{\hbar}{2m} \partial^2 \Psi/ \partial x^2$$

Consider an initial state described by the wavefuntion

$$\Psi(x,0) = \sqrt {(\pi_0(x))}exp(iQx)$$

where Q is a constant and $$\pi_0$$ is a normalized gaussian distribution function with zero mean and variance $$(\sigma_0)^2$$

$$\pi_0(x) = (1/\sqrt{(2\pi)\sigma_0})*exp(\frac{-x^2}{ 2(\sigma_0)^2})$$

Solve the schrodinger equation and show that the probability density $$\pi(x,t) = |\Psi(x,t)|^2 $$ at t>0 is given by

$$\pi(x,t) = (1/\sqrt{(2\pi)\sigma(t))}exp( (-\frac{(x-vt)^2) }{ (2\sigma(t)^2) })$$

What are the formulas $$\sigma(t)$$ and v?

Hint: might be easier to use $$\tau = 2m(\sigma_0)^2/\hbar , l = 2Q(\sigma_0)^2 $$
I tried plugging Psi into the right of the Schrödinger equation but can't get anything close to the solution or anything that is usable. How should I solve this?
 
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First, be careful that you are not trying to put ##\Psi(x,0) ## into the Schrödinger equation. That is the ##t=0## boundary condition. You need ##\Psi(x,t)##.

Recall that ##| \Psi |^2 ## means multiply ##\Psi## by its complex conjugate. So that means that the ##\exp (i Q x) ## factor does not appear in ##\pi (x,t)##. It's just a phase, so when you do the abs-square you get 1.

So maybe ##\Psi(x,t) ## can be obtained by the obvious means of putting the ##t## back into the ##\Psi(x,0)## formula?

$$ \Psi(x,t) = \sqrt{\pi(x,t)} \exp(i Q x)$$

This does give you back the correct ##\Psi(x,0) ##. So now, if you put this in the S.E., and turn the crank, you should get something that involves an equation in ##\sigma(t)##. And the ##(t)## part is trying to suggest that it is only a function of time. Meaning the ##x## parts of the S.E. should be identically solved by the form of ##\Psi(x,t)##. Check that is true. If it's not, can you guess what has to be added to ##\Psi(x,t)## to make it true? Remember that ##\pi(x,t)## can't change, so the additional stuff has to be just a phase.

When you struggle through that, you should be able to pull out a functional form for ##\sigma(t)## and a relation between ##v## and ##Q##.

The hint is telling you that the equation might be simpler if you change the time coordinate to the indicated parameter. It may mean that a bunch of the constants in front of the ##\Psi## are cancelled, meaning your equations are a lot easier to write.
 
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boudreaux said:
Homework Statement:: Solve the Schrödinger equation and show the probability density is as follows
Relevant Equations:: The Schrödinger equation for a free particle is

$$ih(\partial \Psi/\partial t) = -\frac{\hbar}{2m} \partial^2 \Psi/ \partial x^2$$

Consider an initial state described by the wavefuntion

$$\Psi(x,0) = \sqrt {(\pi_0(x))}exp(iQx)$$

where Q is a constant and $$\pi_0$$ is a normalized gaussian distribution function with zero mean and variance $$(\sigma_0)^2$$

$$\pi_0(x) = (1/\sqrt{(2\pi)\sigma_0})*exp(\frac{-x^2}{ 2(\sigma_0)^2})$$

Solve the Schrödinger equation and show that the probability density $$\pi(x,t) = |\Psi(x,t)|^2 $$ at t>0 is given by

$$\pi(x,t) = (1/\sqrt{(2\pi)\sigma(t))}exp( (-\frac{(x-vt)^2) }{ (2\sigma(t)^2) })$$

What are the formulas $$\sigma(t)$$ and v?

Hint: might be easier to use $$\tau = 2m(\sigma_0)^2/\hbar , l = 2Q(\sigma_0)^2 $$

I tried plugging Psi into the right of the Schrödinger equation but can't get anything close to the solution or anything that is usable. How should I solve this?

How do you solve the Schroedinger equation (SDE) for any potential? What's the general method?

##v## must be related to ##Q## in some way, which you may have to work out as part of the solution. Similarly, ##\sigma(t)## represents the standard deviation of the Gaussian at time ##t##. Note that the solution remains a Gaussian, but its standard deviation changes with time, and this is something else that should come out of your solution.

Note that ##\exp{iQx}## is not a phase factor, as it includes the variable ##x##. Do you know or can you guess what this factor represents? Hint: what does ##v## often represent.

Can you intepret the solution? Before you solve it, it might be useful to see whether you can figure out what the solution means.

This problem, I would say, is less than easy! If you are unsure of what you are doing with the SDE, I suggest you find some less complicated examples before returning to this.

If you do press ahead, get your algebra hat on.
 
boudreaux said:
$$\pi_0(x) = (1/\sqrt{(2\pi)\sigma_0})*exp(\frac{-x^2}{ 2(\sigma_0)^2})$$

I'd check that expression. I think it should be:$$\pi_0(x) = \frac{1}{\sigma_0\sqrt{2\pi}}\exp(\frac{-x^2}{ 2(\sigma_0)^2})$$
 
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