Travel Sound Wave: Determine Wavelength, Frequency, etc.

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SUMMARY

The traveling sound wave is represented by the equation D(x,t)=0.48sin(5.6x+84t), where D is in meters and t is in seconds. The amplitude of the wave is 0.48 meters, the wave number k is 5.6, and the angular frequency ω is 84 rad/s. The wavelength λ is calculated as λ = 2π/k, resulting in approximately 1.12 meters. The frequency f is determined using the relation f = ω/(2π), yielding a frequency of approximately 13.39 Hz, while the wave speed v is calculated as v = fλ, resulting in a speed of approximately 15.0 m/s.

PREREQUISITES
  • Understanding of wave motion and properties
  • Familiarity with trigonometric functions and their applications in physics
  • Knowledge of angular frequency and wave number
  • Ability to manipulate algebraic equations
NEXT STEPS
  • Study the relationship between wave speed, frequency, and wavelength using the equation v=fλ
  • Explore the concept of wave number and its significance in wave mechanics
  • Learn about the properties of sine waves and their mathematical representation
  • Investigate the effects of medium on sound wave propagation
USEFUL FOR

Students studying physics, particularly those focusing on wave mechanics, as well as educators teaching sound wave properties and their mathematical representations.

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Homework Statement


A traveling sound wave is represented by D(x,t)=0.48sin(5.6x+84t) with D in meter and t in seconds. Determine wavelength, frequency, amplitude, velocity (including direction) and the maximum speed of the vibrating air.


Homework Equations


Okay, I'm quite confused about this equation, more specifically the fact that it's a function with two variables in it. So I'm not quite sure what to do with it, and whether or not I treat this equation normally. I know how to get the velocity and the max speed normally but I am not quite sure what to do in this specific case. Also I'm not quite sure how to determine the wavelength algebraically.
 
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I'll give you a crash course in wave motion.

If you had a pulse with some arbitrary shape which is traveling to the right with speed v, the actual equation of the pulse will change with time.

If it has form y=f(x) at t=0, then it will have moved to the right a distance vt by time t.
The new position will be: ##y(x,t)=f(x-vt)## (you can try this out with different functions f(x) to get comfortable with this before you deal with sine waves.)

For a sine wave, ##y(x,0)=f(x)=A\sin(kx)## at t=0, at some later time t, it will be given by $$y(x,t)=A\sin(k(x-vt))$$Just to relate what those letters all mean:
A is the amplitude
v is the wave speed
k is the "wave number"
the angular frequency is ##\omega = kv##
the wavelength is ##\lambda = 2\pi/k##

So you can rewrite the equation in different terms:
$$y(x,t)=A\sin(kx-\omega t) =A\sin(kx-2\pi f t)=A\sin2\pi(\frac{x}{\lambda} - \frac{t}{T})$$... which should give you some forms you are used to.

From here you can derive the relation ##v=f\lambda##
 

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