Triangle Math Help: Calculate Angles & Lengths with 46 & 35 Measurements

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This discussion focuses on calculating angles and lengths in a triangle given specific measurements: one side measuring 46 units and a height or distance of 35 units from the midpoint of that side to the opposite vertex. Participants emphasize the importance of precise descriptions and visual representations of the triangle to facilitate accurate calculations. The Pythagorean theorem is referenced as a key tool for determining angles in right triangles, highlighting the necessity of clarity in geometric problems.

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I couldn't find a triangle calculator that input triangle height. Just angles and outer length.

I have a triangle with 46 at one length and a line from center of length going to opposite corner that is 35. How can I calculate all angles from that? Sorry. I dumb.
 
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LightningInAJar said:
I couldn't find a triangle calculator that input triangle height. Just angles and outer length.

I have a triangle with 46 at one length and a line from center of length going to opposite corner that is 35. How can I calculate all angles from that? Sorry. I dumb.
So you have a baseline, a height, and two equal angles since the height is at the center of the baseline. This gives you two identical right triangles. The sum of all angles in a triangle equals 180°, and for right triangles, we have Pythagoras: ##h^2+(b/2)^2=c^2## where ##h## is the height and ##b## the baseline.
[Moderator's note: moved from a technical forum.]
 
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Is 35 the right-angle height or is it going to the opposite corner on a slope?
 
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35 was the distance line from the 46 line to opposite side.
 
LightningInAJar said:
35 was the distance line from the 46 line to opposite side.
So post #2 contains all you need to know. You have to show us some effort from your side.
 
LightningInAJar said:
35 was the distance line from the 46 line to opposite side.
That doesn't exactly answer my question. We must be very precise in this. If the 46-line is flat on the ground, is the 35 the height of the vertex opposite to the 46-line? Or is it a tilted distance from the center of the 46-line to the opposite vertex? You might want to show a drawing of the situation.
 
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Maybe '35' is the angle of the opposite corner ?
 
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LightningInAJar,
DO YOU HAVE A PICTURE? WILL YOU DESCRIBE YOUR TRIANGLE PRECISELY?
 
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LightningInAJar said:
I have a triangle with 46 at one length and a line from center of length going to opposite corner that is 35. How can I calculate all angles from that? Sorry. I dumb.

symbolipoint said:
DO YOU HAVE A PICTURE? WILL YOU DESCRIBE YOUR TRIANGLE PRECISELY?
We're 8 posts into this thread because of the poor description, and we still don't know what the triangle looks like. A picture with the sides labelled with their lengths and the known angles labelled would have been very helpful.
 
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  • #10
LightningInAJar said:
35 was the distance line from the 46 line to opposite side.
Depends how you mean the term distance here. The Euclidean distance between two points or the line that connects the two points and is perpendicular to the side of length 46?
 
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  • #11
I think, by the time we actually get as far as finding out what the question is, everybody's going to be too tired to help with the answer.
 
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  • #12
Thread closed. @LightningInAJar, please start a new thread that shows a complete description of the triangle you're interested in.
 
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