MHB Tricks for Saving Money on Groceries

[bearn]

 

[skeeter]

no ... you found the derivative, not the antiderivative.

$\displaystyle \int \dfrac{3}{2}x^2 + 5x + C \, dx = \dfrac{x^3}{2} + \dfrac{5}{2}x^2 + Cx + K$

 

[bearn]

no ... you found the derivative, not the antiderivative.

$\displaystyle \int \dfrac{3}{2}x^2 + 5x + C \, dx = \dfrac{x^3}{2} + \dfrac{5}{2}x^2 + Cx + K$

Where is your answer based from? What rule, if there is?

 

[skeeter]

Maybe you meant ...

$\displaystyle \int 3x+5 \, dx = \dfrac{3}{2}x^2 + 5x + C$ ?

in any case, watch the video

 

[Kansas Boy]

As skeeter first said, you went "the wrong way"- you found the derivative, not the integral. $\frac{d(\frac{3}{2}x^2+ 5x+ C)}{dx}= 3x+ 5$