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SUMMARY

This discussion centers around the mathematical concepts of derivatives and antiderivatives, specifically addressing the integration of polynomial functions. Participants clarify that the integral of the function $\displaystyle \int \dfrac{3}{2}x^2 + 5x + C \, dx$ results in $\dfrac{x^3}{2} + \dfrac{5}{2}x^2 + Cx + K$, while emphasizing the importance of understanding the distinction between finding a derivative and an antiderivative. The conversation highlights the necessity of correctly applying integration rules to avoid confusion.

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  • Understanding of basic calculus concepts, including derivatives and integrals.
  • Familiarity with polynomial functions and their properties.
  • Knowledge of integration techniques and rules.
  • Ability to interpret mathematical notation and expressions.
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  • Study the Fundamental Theorem of Calculus to grasp the relationship between derivatives and integrals.
  • Practice solving integrals of polynomial functions, focusing on correct application of integration rules.
  • Explore advanced integration techniques, such as integration by parts and substitution.
  • Review common mistakes in calculus to improve accuracy in solving problems.
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Students, educators, and anyone looking to deepen their understanding of calculus, particularly in the areas of differentiation and integration of polynomial functions.

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no ... you found the derivative, not the antiderivative.

$\displaystyle \int \dfrac{3}{2}x^2 + 5x + C \, dx = \dfrac{x^3}{2} + \dfrac{5}{2}x^2 + Cx + K$
 
skeeter said:
no ... you found the derivative, not the antiderivative.

$\displaystyle \int \dfrac{3}{2}x^2 + 5x + C \, dx = \dfrac{x^3}{2} + \dfrac{5}{2}x^2 + Cx + K$
Where is your answer based from? What rule, if there is?
 
Maybe you meant ...

$\displaystyle \int 3x+5 \, dx = \dfrac{3}{2}x^2 + 5x + C$ ?

in any case, watch the video

 
Last edited by a moderator:
As skeeter first said, you went "the wrong way"- you found the derivative, not the integral. $\frac{d(\frac{3}{2}x^2+ 5x+ C)}{dx}= 3x+ 5$
 

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