Tricky Logical Problem: Solving for \forallx\forally\existsz

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SUMMARY

The logical statement \forall x \forall y \exists z (x < z \rightarrow x \geq y) is confirmed as true in the context of Discrete Mathematics. The reasoning hinges on the fact that if z is chosen to be less than or equal to x, the implication (x < z) becomes false, rendering the entire statement true regardless of the truth value of A. This understanding clarifies the conditions under which the logical implications hold.

PREREQUISITES
  • Understanding of logical implications in predicate logic
  • Familiarity with quantifiers: universal (\forall) and existential (\exists)
  • Basic knowledge of Discrete Mathematics concepts
  • Ability to interpret mathematical statements and implications
NEXT STEPS
  • Study the properties of logical implications in predicate logic
  • Learn about the use of quantifiers in mathematical proofs
  • Explore examples of similar logical statements and their truth conditions
  • Review Discrete Mathematics textbooks focusing on logical reasoning
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Students of Discrete Mathematics, educators teaching logic, and anyone interested in understanding logical implications and quantifiers in mathematical contexts.

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Homework Statement


This is a problem I have been had some troubles understanding in my Discrete Mathematics course.

[PLAIN]http://i.imgur.com/HTUNr7f.png[/PLAIN]


[itex]\forall[/itex]x[itex]\forall[/itex]y[itex]\exists[/itex]z(x<z[itex]\rightarrow[/itex]x≥y)



Homework Equations



I know that this statement is true, according to the solutions page, but I just cannot comprehend why?



The Attempt at a Solution



Does anyone have any ideas?
 

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The statement is true, because if you choose z to be less or equal to x, then (x < z) is a false statement, so (x < z ) -> A is always true, regardless of "A".
 

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