Trig Function Help: Get Answers Now

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    Function Trig
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Homework Help Overview

The discussion revolves around a trigonometric problem involving the double angle formula for cosine, specifically cos(2t). Participants are attempting to clarify the problem's requirements and the values needed for calculations.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants inquire about the specifics of the problem, including the variable involved and the need for using the double angle formula. There are discussions about finding values for sine and cosine using a reference triangle and the relationships between cotangent and tangent.

Discussion Status

Several participants are actively engaging with the problem, sharing their interpretations and calculations. Some guidance has been offered regarding the use of trigonometric identities and the reference triangle method, though no consensus has been reached on the final answer.

Contextual Notes

There is mention of a teacher's requirement to understand the concepts without a calculator for a test, which adds a layer of complexity to the discussion. Participants are also exploring the implications of the given cotangent value.

Eric Manuel
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thanks
 
Last edited:
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Can you give the entire problem?
 
Jimmy Johnson said:
Can you give the entire problem?

all that's given is that
 
What is the question? What are you asked to find?
 
MostlyHarmless said:
What is the question? What are you asked to find?
what is =cos2x
 
What is x supposed to be? Is the given problem in terms of t? Are you trying to solve for t and then plug that value in for x?
 
oh my bad its cos2t

its basically asking you to use the double angle formula
but I am not sure how to find those values
 
If you're simply trying to find t, then use cot = 1/tan... If you have a value for t why do you need to use the double angle identities?
 
to find what cos2t is ...

you can find what tan is from cot
then i drew a triangle and got the hypot to be sqrt(41)

but how do i do that math

formula for cos2t = cos^2(t) - sin^2(t)
 
  • #10
Are you forbidden from using a calculator?
 
  • #11
Jimmy Johnson said:
Are you forbidden from using a calculator?

teacher said u can use it
but need to know how to do it without one for test
 
  • #12
Well that may have been useful information at the start...

you have cot = -5/4, find what tan is then recall tan = sin/cos ... or recall cot = cos/sin...
 
  • #13
well i worked it out and i believe i got the answer to be 9/41
 
  • #14
That's what I'm getting
 

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