Trig Identities that I can't get a grip on

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Homework Help Overview

The discussion revolves around proving a trigonometric identity involving tangent functions and sine functions. The original poster expresses difficulty in manipulating the identity and understanding the implications of substituting specific values.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to simplify the identity by substituting known values, leading to confusion about the resulting equation. Some participants suggest using specific trigonometric identities to aid in the proof.

Discussion Status

Participants are exploring different approaches to the problem, with some providing guidance on relevant trigonometric identities. There is a recognition of the original poster's misunderstanding, and a suggestion to redefine variables for clarity has been confirmed by another participant.

Contextual Notes

The original poster questions the validity of their approach and expresses uncertainty about advanced formatting options in the forum.

Fractal314
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[tan(pi/4+x)-tan(pi/4-x)]/[tan(pi/4+x)+tan(pi/4-x)]=2sinxcosx

I tried to prove this trig identity but I an really stuck. I think tan of pi/4 is '1', and if I do that then my numerator becomes zero, thus zero=2sinxcosx. But that can't be right, so I don't know what to do now.


LS= (1+tanx-1-tanx)/(1+tanx+1-tanx)

I get 0=2sinxcosx

Any thoughts? Also, I am wondering where this advanced formatting option is or how to do it.
 
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You will need to use the identities

tan(A+B)=(tanA+tanB)/(1-tanA*tanB)

tan(A-B)=(tanA-tanB)/(1+tanA*tanB)
 
Thankyou Overt, I did not see it.

So would I be right in assigning 'y' as pi/4? and let 'x' be 'x'?

For tan(pi/4+x) I will instead get (tanx+tanpi/4)/(1-tanxtanpi/4)?
 
Correct!
 

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