Inequalities (trig) + Attempted

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Homework Help Overview

The discussion revolves around solving the trigonometric equation tan(x) + 3cot(x) = 4. Participants are exploring the implications of their attempts to find solutions for both tan(x) = 1 and tan(x) = 3, while considering the constraints of their homework environment.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the transformation of the original equation into a quadratic form and the subsequent solutions for tan(x). Questions arise regarding the representation of tan^-1(3) in radians without the use of calculators, and the validity of previous steps taken in the problem-solving process.

Discussion Status

Some participants have provided guidance on how to express solutions for tan(x) = 1 and tan(x) = 3, while others are questioning the feasibility of expressing tan^-1(3) in terms of pi. There is an ongoing exploration of the steps taken, with some participants seeking confirmation of their reasoning.

Contextual Notes

Participants note the restriction of not using calculators in their school, which influences their approach to finding solutions. There is also a mention of the need to clarify the notation used for the variable n in the context of periodic solutions.

lovemake1
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Homework Statement



tanx + 3cotx = 4

Homework Equations





The Attempt at a Solution



Heres my attempt:

tanx + 3/tanx - 4 = 0
(tan^2x -4tanx + 3) / tanx = 0

tan^2x - 4 tanx + 3

(tanx - 3 ) (tanx - 1 ) = 0

tan = 3, tan = 1

im not sure about tan = 3, but for tan = 1 , pi/4 +180n,
is this correct? if it is how would i go about findin solutions for tan=3.

please help,
thanks.
 
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The same way you solved tanx=1

tanx=3, the principle angle is tan-1(3)
 
how would we represent tan^-1(3) interms of radians ?
calculators are not allowed in our school, is there a way ?
 
lovemake1 said:
how would we represent tan^-1(3) interms of radians ?
calculators are not allowed in our school, is there a way ?

Unfortunately there is not.
 
hmm..
so we just find solutions for tan = 1 ?
 
lovemake1 said:
im not sure about tan = 3, but for tan = 1 , pi/4 +180n,
is this correct? if it is how would i go about findin solutions for tan=3.
"pi/4 +180n" -> Don't mix degree and radian measure. Also, state what "n" is. You should write
\frac{\pi}{4} + n \pi, n \in \mathbb{Z}

lovemake1 said:
hmm..
so we just find solutions for tan = 1 ?
No, you still need both solutions. The other could be written as
\tan^{-1} 3 + n \pi, n \in \mathbb{Z}
 
tan^-1(3) + npi
how do you write that interms of pi?

i've never seen anything like that. could you please give me an example?
 
lovemake1 said:
tan^-1(3) + npi
how do you write that interms of pi?

i've never seen anything like that. could you please give me an example?

you can't write tan-1(3) in terms of pi. That is why you have to leave it as is.
 
ok, just to make sure.. are my previous steps correct?
just to double check. thanks
 
  • #10
lovemake1 said:
ok, just to make sure.. are my previous steps correct?
just to double check. thanks

Yes they are correct.
 

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