High School Trig Problem Altitudes of Parallelogram

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The discussion focuses on finding the area of a parallelogram with altitudes measuring 8 and 10, intersecting at an angle with a sine of 1/4. The original poster is struggling to visualize the problem and seeks assistance. Participants suggest posting in the appropriate forum for homework help and recommend including relevant equations and attempts at solving the problem. Additionally, they encourage uploading images for better clarity. The conversation emphasizes the importance of providing context and details for effective assistance.
Trepid
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Basically the altitudes of a parallelogram have two lengths, 8 and 10 and they intersect at an angle whose sine is 1/4. I'm attempting to find the area of the parallelogram.

I'm having trouble creating a good picture of it. Seeing if I could receive some help, thanks!
 
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Trepid said:
Basically the altitudes of a parallelogram have two lengths, 8 and 10 and they intersect at an angle whose sine is 1/4. I'm attempting to find the area of the parallelogram.

I'm having trouble creating a good picture of it. Seeing if I could receive some help, thanks!
Welcome to the PF. :smile:

Is this for schoolwork? If so, you need to post it in the Homework Help, Pre-Calculus Math forum, and fill out the Template there showing the Relevant Equations and your Attempt at Solving it.

You can also upload a PDF or JPEG image by using the Upload button in the lower right of the Edit window.
 

Thread 'Area of Overlapping Squares'

Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?
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