i want the most general solution for sin6x=sin4x-sin2x
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May 10, 2008 #2 rock.freak667 Homework Helper 6,230 31 sin6x=sin4x-sin2x sin6x-sin4x+sin2x=0 Then remember that [tex]sinP+sinQ=2sin(\frac{P+Q}{2})cos(\frac{P-Q}{2})[/tex]
sin6x=sin4x-sin2x sin6x-sin4x+sin2x=0 Then remember that [tex]sinP+sinQ=2sin(\frac{P+Q}{2})cos(\frac{P-Q}{2})[/tex]