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Trigonometric inverse functions

  1. May 10, 2008 #1
    i want the most general solution for
    sin6x=sin4x-sin2x
     
  2. jcsd
  3. May 10, 2008 #2

    rock.freak667

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    Homework Helper

    sin6x=sin4x-sin2x

    sin6x-sin4x+sin2x=0

    Then remember that

    [tex]sinP+sinQ=2sin(\frac{P+Q}{2})cos(\frac{P-Q}{2})[/tex]
     
  4. May 12, 2008 #3
    thanks
     
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