Trigonometric inverse functions

  • Thread starter lizzie
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  • #1
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i want the most general solution for
sin6x=sin4x-sin2x
 

Answers and Replies

  • #2
rock.freak667
Homework Helper
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sin6x=sin4x-sin2x

sin6x-sin4x+sin2x=0

Then remember that

[tex]sinP+sinQ=2sin(\frac{P+Q}{2})cos(\frac{P-Q}{2})[/tex]
 
  • #3
25
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thanks
 

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