- #1

Roymcloud93

- 1

- 0

what would i do here? i have checked most math sites and they don't tell me what do do if its equal to zero

IF its equal to zero does that change anything or what?

You are using an out of date browser. It may not display this or other websites correctly.

You should upgrade or use an alternative browser.

You should upgrade or use an alternative browser.

- Thread starter Roymcloud93
- Start date

- #1

Roymcloud93

- 1

- 0

what would i do here? i have checked most math sites and they don't tell me what do do if its equal to zero

IF its equal to zero does that change anything or what?

- #2

Tedjn

- 737

- 0

- #3

fedaykin

- 138

- 3

Think of it as ax^2 + bx + c = 0.

Now, since a = 1, what adds up to b, but when multiplied gives c?

You might also look up the Foil Method.

http://www.algebrahelp.com/lessons/factoring/trinomial/

While it is true that quadratic with a discriminant greater or equal to zero may be written as the product of two binomials (well, I'm not certain, but sometimes it seems to require a coefficient), factoring can sometimes be very difficult.

This case is easy to factor, but if you come across one that you can't get right, try the following.

Use the quadratic equation:

Suppose you have a trinomial, ax^2+bx+c=0

To solve use x =( -b + sqrt(b^2 -4ac)) / 2a to find one answer.

Sorry, let me try that with LaTex.

[tex]\ x = (-b\pm \sqrt{b^2 -4ac})/2a[/tex]

Hmm ... the x isn't showing up, but oh well.

Now, since a = 1, what adds up to b, but when multiplied gives c?

You might also look up the Foil Method.

http://www.algebrahelp.com/lessons/factoring/trinomial/

While it is true that quadratic with a discriminant greater or equal to zero may be written as the product of two binomials (well, I'm not certain, but sometimes it seems to require a coefficient), factoring can sometimes be very difficult.

This case is easy to factor, but if you come across one that you can't get right, try the following.

Use the quadratic equation:

Suppose you have a trinomial, ax^2+bx+c=0

To solve use x =( -b + sqrt(b^2 -4ac)) / 2a to find one answer.

Sorry, let me try that with LaTex.

[tex]\ x = (-b\pm \sqrt{b^2 -4ac})/2a[/tex]

Hmm ... the x isn't showing up, but oh well.

Last edited:

- #4

HallsofIvy

Science Advisor

Homework Helper

- 43,021

- 970

No, you don't- and that's the problem!ko so i have the problem y^2+13y+40=0

What you do with anwhat would i do here? i have checked most math sites and they don't tell me what do do if its equal to zero

IF its equal to zero does that change anything or what?

But it might be that the "problem" is just to factor the polynomial. It might be that the problem is to find all values of x for which the equation is NOT true! (All numbers except -8 and -5.)

Don't focus on the

(If my English teacher were to tell me "Jimmy is going to the swimming pool", and then look at me expectantly, I might look back quizzically and then say "Okaaay, what do you want

Share:

- Replies
- 0

- Views
- 269

- Replies
- 2

- Views
- 1K

- Replies
- 55

- Views
- 2K

- Last Post

- Replies
- 22

- Views
- 862

- Replies
- 3

- Views
- 391

- Replies
- 2

- Views
- 1K

- Last Post

- Replies
- 2

- Views
- 404

- Last Post

- Replies
- 6

- Views
- 395

- Last Post

- Replies
- 20

- Views
- 231

- Last Post

- Replies
- 1

- Views
- 339