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Triple scalar product/coplanarity of

  1. Nov 7, 2012 #1
    1. The problem statement, all variables and given/known data
    Suppose that a,b,c are nonparallel nonzero vectors, and that [itex] ( a \times b) \cdot c = 0 [/itex]. Show that c is expressible as a linear combination of a and b. Avoid geometric arguments (that is, try to stick to vector algebra and symbols in the proof).


    2. Relevant equations



    3. The attempt at a solution
    The geometric interpretation is that because the triple scalar product of a,b,c is 0, the three vectors are coplanar. Thus, c lies on the plane P determined by a,b. In other words, c is an element of the set of vectors given by the parametrization of the plane P, namely, [itex] P = (t_{1}a + t_{2}b: t_{1},t_{2} \epsilon ℝ) [/itex] And thus, c is expressible as a linear combination of a and b.

    But I'm trying to prove this algebraically using vector identities, matrices, and the like. No geometry. Any ideas? I appreciate all help thanks!

    BiP
     
    Last edited: Nov 7, 2012
  2. jcsd
  3. Nov 8, 2012 #2

    HallsofIvy

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    Staff Emeritus
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    So you have to do this the hard way? Then let a= <a, b, c>, b= <p, q, r>, and c= <x, y, z>. Calculate the coordinates of [itex](a\times b)\cdot c[/itex] and set them equal to 0.
     
  4. Nov 8, 2012 #3
    Thanks Ivy. Is there any faster way around it, that involves using vector identities and the like?

    BiP
     
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