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seacow
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Homework Statement
What's the mass (lb) of a soil in an acre 6 inches deep with bulk density of 1.2 g/cm3?
AI Thread Summary
To determine the mass of soil in an acre 6 inches deep with a bulk density of 1.2 g/cm3, the volume must first be calculated. An acre has a volume of 21,780 ft3 when considering half an acre. The conversion from cubic feet to cubic centimeters is essential, as 1 cubic foot equals 28,316.8466 cm3. The mass can then be calculated using the formula that incorporates the bulk density and the converted volume. Accurate unit conversions are crucial for solving this density mass problem effectively.
Neglect gravity other than that of water; neglect friction.
F1=ρgsh=1000*10*1*(1+4)=50000 N;
F1=ρgsh=1000*10*0.1*4=4000 N;
F3=50000-4000=46000 N?
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook.
Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water.
I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Kindly see the attached pdf. My attempt to solve it, is in it.
I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction.
I'm not able to figure out, why my solution is wrong, if it is wrong .
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