MHB True or False Question about Square Matrices

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For every square matrix A, the expression C = A(A^t) + (A^t)A is confirmed to be symmetric. This can be demonstrated by calculating the transpose of C and applying the properties of transposes, specifically that the transpose of a sum is the sum of the transposes and the transpose of a product reverses the order of multiplication. The discussion emphasizes the importance of these rules in proving the symmetry of the matrix C. Ultimately, the conclusion is that the statement about C being symmetric is true for all square matrices A.
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[MHB thread moved to the PF schoolwork forums by a PF Mentor]

For every square matrix A, C=A(A^t)+(A^t)A is symmetric.
 
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TheScienceAlliance said:
For every square matrix A, C=A(A^t)+(A^t)A is symmetric.

Have you considered calculating the transpose of C, using the rules <br /> \begin{split}<br /> (A + B)^T &amp;= A^T + B^T, \\<br /> (AB)^T &amp;= B^TA^T? \end{split}
 
The working out suggests first equating ## \sqrt{i} = x + iy ## and suggests that squaring and equating real and imaginary parts of both sides results in ## \sqrt{i} = \pm (1+i)/ \sqrt{2} ## Squaring both sides results in: $$ i = (x + iy)^2 $$ $$ i = x^2 + 2ixy -y^2 $$ equating real parts gives $$ x^2 - y^2 = 0 $$ $$ (x+y)(x-y) = 0 $$ $$ x = \pm y $$ equating imaginary parts gives: $$ i = 2ixy $$ $$ 2xy = 1 $$ I'm not really sure how to proceed from here.