MHB True or False Question about Square Matrices

  • Thread starter Thread starter TheScienceAlliance
  • Start date Start date
  • Tags Tags
    Matrices Square
AI Thread Summary
For every square matrix A, the expression C = A(A^t) + (A^t)A is confirmed to be symmetric. This can be demonstrated by calculating the transpose of C and applying the properties of transposes, specifically that the transpose of a sum is the sum of the transposes and the transpose of a product reverses the order of multiplication. The discussion emphasizes the importance of these rules in proving the symmetry of the matrix C. Ultimately, the conclusion is that the statement about C being symmetric is true for all square matrices A.
TheScienceAlliance
Messages
6
Reaction score
0
[MHB thread moved to the PF schoolwork forums by a PF Mentor]

For every square matrix A, C=A(A^t)+(A^t)A is symmetric.
 
Last edited by a moderator:
Physics news on Phys.org
TheScienceAlliance said:
For every square matrix A, C=A(A^t)+(A^t)A is symmetric.

Have you considered calculating the transpose of C, using the rules <br /> \begin{split}<br /> (A + B)^T &amp;= A^T + B^T, \\<br /> (AB)^T &amp;= B^TA^T? \end{split}
 
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
Back
Top