True vs. Apparent weight question

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SUMMARY

The discussion centers on calculating the true weight of an astronaut in a rocket with an apparent weight of 1.35x103N and an upward acceleration of 14.7 m/s2. The astronaut's true weight is derived using Newton's second law, where the normal force (apparent weight) is balanced against the gravitational force (true weight). The confusion arises from the distinction between apparent weight and true weight, with the correct approach involving the equation Fn - Fg = ma. The final calculation requires substituting the mass derived from Fg = mg into the equation.

PREREQUISITES
  • Understanding of Newton's second law (F = ma)
  • Knowledge of gravitational force calculations (Fg = mg)
  • Ability to interpret free body diagrams
  • Familiarity with the concepts of apparent weight versus true weight
NEXT STEPS
  • Study the application of Newton's second law in various contexts
  • Learn how to construct and analyze free body diagrams
  • Explore the differences between apparent weight and true weight in physics
  • Practice problems involving forces in accelerating systems
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Students in physics, educators teaching mechanics, and anyone interested in understanding forces in non-inertial reference frames.

pauladancer
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Homework Statement


An astronaut in a rocket has an apparent weight of 1.35x103N [down]. If the acceleration of a rocket is 14.7 m/s2 [up] near Earth's surface, what is the astronaut's true weight? The acceleration due to gravity on Earth's surface is about 9.81 m/s2 [down].
Mass of Earth is 5.97x1024, not sure if that's needed or not.

Homework Equations


Fnet = ma
Fg = Gm1m2 / r2
g = Gm(source) / r2
g = Fg / m(test)

The Attempt at a Solution


I'm confused about what I should be solving for (I think it should be Fg), if the apparent weight is the normal force shouldn't it be directed up? I'm also confused about which acceleration to use and where, also which formula to use. So I'm pretty lost! Any help would be greatly appreciated :)
 
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Yes the normal force is directed up on the astronaut and is equal to the so-called apparent weight. Just use Newton's 2nd law and your first and last equation after first determining the other force besides the normal force acting on the astronaut. No need to use the middle 2 equations since g is already given.
 
pauladancer said:

Homework Statement


An astronaut in a rocket has an apparent weight of 1.35x103N [down]. If the acceleration of a rocket is 14.7 m/s2 [up] near Earth's surface, what is the astronaut's true weight? The acceleration due to gravity on Earth's surface is about 9.81 m/s2 [down].
Mass of Earth is 5.97x1024, not sure if that's needed or not.

Homework Equations


Fnet = ma
Fg = Gm1m2 / r2
g = Gm(source) / r2
g = Fg / m(test)

The Attempt at a Solution


I'm confused about what I should be solving for (I think it should be Fg), if the apparent weight is the normal force shouldn't it be directed up? I'm also confused about which acceleration to use and where, also which formula to use. So I'm pretty lost! Any help would be greatly appreciated :)
Have you drawn a free body diagram, or do you think you have advanced beyond the point where you need to use free body diagrams?
 
PhanthomJay said:
Yes the normal force is directed up on the astronaut and is equal to the so-called apparent weight. Just use Newton's 2nd law and your first and last equation after first determining the other force besides the normal force acting on the astronaut. No need to use the middle 2 equations since g is already given.
I'm still a bit confused, I solved for the mass using Fg = (mass)(gravity) :
1.35x103N = (mass)(9.81m/s2)
mass = 137.614 kg

But then after I plugged it into my formula Fn - Fg = ma I got a true weight of -672 N. I'm not sure where I went wrong.
 
Chestermiller said:
Have you drawn a free body diagram, or do you think you have advanced beyond the point where you need to use free body diagrams?
I have drawn the free body diagram, and I have come up with the equation Fn - Fg = ma. However when I plug in the mass that I found (if that's even the right mass) I get a negative answer.
 
How much is the system accelerating by?
 
You have mistakenly confused apparent weight with true weight. Fg is true weight, Fn is apparent weight. Your equation is correct, but you need to make the proper substitutions. The normal force is not equal to mg.
 
Sho Kano said:
How much is the system accelerating by?
14.7 m/s2 up.
 
PhanthomJay said:
You have mistakenly confused apparent weight with true weight. Fg is true weight, Fn is apparent weight. Your equation is correct, but you need to make the proper substitutions. The normal force is not equal to mg.
Oh I see! I know why that is wrong, but I'm still not sure about how to find the mass of the astronaut correctly. I think I need that first to answer the question.
 
  • #10
pauladancer said:
I have drawn the free body diagram, and I have come up with the equation Fn - Fg = ma. However when I plug in the mass that I found (if that's even the right mass) I get a negative answer.
Good. Now plug in ##F_g=mg## and solve for ##F_n##
 
  • #11
pauladancer said:
Oh I see! I know why that is wrong, but I'm still not sure about how to find the mass of the astronaut correctly. I think I need that first to answer the question.
Yes that is correct. F_n is given. F_g is mg. Solve for m using your equation that you determined from your free body diagram and Newton 2, substituting in the given value for a. Then solve for F_g.
 

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