Trying to understand an integration example

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SUMMARY

The discussion revolves around understanding a mathematical integration example involving the substitution \( a = \frac{x - RP}{\sqrt{2} \Delta RP} \). The key conclusion is that by differentiating this substitution with respect to \( x \), one arrives at \( \frac{da}{dx} = \frac{1}{\sqrt{2} \Delta RP} \), leading to the relationship \( dx = \sqrt{2} \Delta RP \, da \). This clarification resolves the confusion regarding the treatment of constants during differentiation.

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  • Understanding of calculus, specifically differentiation.
  • Familiarity with substitution methods in integration.
  • Knowledge of variables and constants in mathematical expressions.
  • Basic grasp of the concepts of limits and continuity.
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  • Study the principles of differentiation in calculus.
  • Learn about substitution techniques in integral calculus.
  • Explore the concept of treating constants in mathematical derivatives.
  • Review examples of integration involving variable substitutions.
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Students and professionals in mathematics, particularly those studying calculus, as well as educators looking to clarify integration techniques and differentiation principles.

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Hello.

I am having some trouble understanding an integration example we have. I have written it out in the attached pdf. I would be grateful if someone can help me undertand what is going on.

I assume you let a = (x-RP)/(√2 ΔRP) da to make the process easier, but I am, not sure how that becomes

1/(√2 ΔRP) dx

I thought if we took the top line to be a constant, that should have come out as zero?

-S
 

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You make the substitution a = (x-RP)/(√2 ΔRP) , then take the derivative of this with respect to x. Everything but x is treated as a constant, so this gives
da/dx = 1/(√2 ΔRP), or dx = (√2 ΔRP) da.
 
Hello,

Thanks for the reply. Right, yea, I think I understand that ...I will run through it a few times just to make sure.

Thanks.

-S
 

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