- #1

kalery

- 19

- 0

You are using an out of date browser. It may not display this or other websites correctly.

You should upgrade or use an alternative browser.

You should upgrade or use an alternative browser.

- Thread starter kalery
- Start date

- #1

kalery

- 19

- 0

- #2

lbrits

- 410

- 3

So now you just need to come to grips with the fact that the kinetic energy is negative. In quantum mechanics, the kinetic energy is an operator acting on a wavefunction, and in 1D is given by [itex]-\hbar^2 \frac{d}{dx}[/itex]. If the kinetic energy is negative, it means that the wavefunction is a growing or (usually) decaying, instead of oscillating. Think of this operator acting on [tex]\psi(x) = e^{-\lambda x}[/tex], versus [tex]\psi(x) = e^{i k x}[/tex].

- #3

kensaurus

- 9

- 0

What do you mean by kinetic energy is an operator acting on a wavefunction" and "wavefunction is a growing or (usually) decaying, instead of oscillating"?

- #4

malawi_glenn

Science Advisor

Homework Helper

Gold Member

- 5,994

- 1,415

kensaurus: Read an introductory text on quantum mechanics.

Share:

- Last Post

- Replies
- 3

- Views
- 785

- Last Post

- Replies
- 4

- Views
- 554

- Last Post

- Replies
- 9

- Views
- 855

- Replies
- 7

- Views
- 486

- Last Post

- Replies
- 4

- Views
- 287

- Last Post

- Replies
- 3

- Views
- 354

- Replies
- 14

- Views
- 648

- Last Post

- Replies
- 6

- Views
- 395

- Last Post

- Replies
- 4

- Views
- 531

- Replies
- 32

- Views
- 443