Twisting at shear center / centroid

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SUMMARY

The discussion centers on the confusion regarding the application of force through the centroid versus the shear center in a C-channel cross-section. It is established that when a force is applied through the centroid, the channel will experience bending and twisting unless the force is also applied at the shear center, which is located outside the C-channel. The notes clarify that to prevent twisting, the force must be applied at the shear center, denoted as point O, rather than solely through the centroid.

PREREQUISITES
  • Understanding of shear center and centroid concepts in structural engineering
  • Familiarity with C-channel cross-section properties
  • Knowledge of bending and twisting behavior in beams
  • Basic grasp of static equilibrium principles
NEXT STEPS
  • Study the relationship between shear center and centroid in various cross-sectional shapes
  • Learn about the effects of eccentric loading on structural members
  • Investigate methods to calculate the shear center for different cross-sections
  • Explore practical applications of shear center concepts in structural design
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Structural engineers, civil engineering students, and anyone involved in the design and analysis of beam structures will benefit from this discussion.

fonseh
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Homework Statement


In the notes , the author stated that when the force is applied through the centorid of cross section , the channel will bend and twist.
but , on the second page , the author stated that the shear center lies on an axis of symmetry of member's cross sectional area...
So, i am confused whether the member will twist or not when the force P is applied thru the centroid or shear center ...

Why the shear center is located at O , which is located outside of the C channel ?

Homework Equations

The Attempt at a Solution


Is there anything wrong with the notes ? [/B]
 

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In the notes , it's also stated that to prevent twisting , the P should be applied at O , does it mean we have to apply the force thru the centoid and also at the O at the same time to prevent twisting ? I'm confused
 
Bump
 
what is the meaning of the force is applied along the once vertical , unsymmetrical axis that passes thru centroid ? Since the applied force already passing thru centroid , it's already the symmertical axis , right ?
 

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