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## Homework Statement

A stepped solid shaft of circular cross section is rigidly clamped at ends A and D and loaded by twisting moments T1= 1kN.m and T2 = 1.5kN.m at points B and C. The material is steel for which G = 84x10^9 N/m^2, the length L of the shaft is 500mm, and the diameters of AB and CD are both 30 mm while that of BC is 50 mm. Determine the angle of twist at C and the peak torsional shearing stress.

http://images.4chan.org/sci/src/1362606506659.png

## Homework Equations

Angle of twist θ= TL/JG

max torsional shearing stress τmax = Tc/J

centroidal moment of inertia J = (∏c^4)/2

## The Attempt at a Solution

I have not attempted a solution because I do not know how to take into account that the shaft is rigidly clamped at both ends and what side to start from. Also, I do not know how the Torque at B (T1) comes into play with the angle of twist at c, I would imagine it increases the angle because it is in the same direction of Torque at C (T2)

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