Angle of Twist and Peak Torsional Shearing Stress

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Discussion Overview

The discussion revolves around a homework problem involving a stepped solid shaft subjected to twisting moments. Participants are exploring the calculation of the angle of twist at a specific point and the peak torsional shearing stress, considering the effects of rigid clamping at both ends and multiple applied torques.

Discussion Character

  • Homework-related
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant expresses uncertainty about how to account for the rigid clamping at both ends of the shaft and how to incorporate the torque at point B into the calculations for the angle of twist at point C.
  • Another participant suggests using the equations of statics to find the reactions at the clamped ends A and D to maintain equilibrium.
  • A participant questions whether to analyze the shaft in separate sections (AB, BC, and CD) or just as two sections (AB and CD) to determine the reactions at A and D.
  • There is a mention that the total angle of the shaft is zero due to the clamping, leading to confusion about how to sum the angles of the individual sections.
  • One participant acknowledges confusion regarding the application of two torques and how to formulate the static equations accordingly.
  • A link to a similar problem is provided to illustrate a method for addressing static indeterminacy in torsion problems.
  • A later reply indicates that one participant believes they have resolved their confusion regarding the problem.

Areas of Agreement / Disagreement

Participants do not appear to reach a consensus on the best approach to solve the problem, with multiple viewpoints on how to handle the statically indeterminate nature of the shaft and the application of multiple torques.

Contextual Notes

Participants express limitations in their understanding of how to apply static equilibrium equations in the context of multiple torques and rigid constraints, indicating potential gaps in foundational knowledge related to torsion and statically indeterminate structures.

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Homework Statement



A stepped solid shaft of circular cross section is rigidly clamped at ends A and D and loaded by twisting moments T1= 1kN.m and T2 = 1.5kN.m at points B and C. The material is steel for which G = 84x10^9 N/m^2, the length L of the shaft is 500mm, and the diameters of AB and CD are both 30 mm while that of BC is 50 mm. Determine the angle of twist at C and the peak torsional shearing stress.

http://images.4chan.org/sci/src/1362606506659.png

Homework Equations


Angle of twist θ= TL/JG
max torsional shearing stress τmax = Tc/J
centroidal moment of inertia J = (∏c^4)/2

The Attempt at a Solution


I have not attempted a solution because I do not know how to take into account that the shaft is rigidly clamped at both ends and what side to start from. Also, I do not know how the Torque at B (T1) comes into play with the angle of twist at c, I would imagine it increases the angle because it is in the same direction of Torque at C (T2)
 
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You have the start of a FBD. Use the equations of statics to find the reactions required at A and D to keep the shaft in equilibrium.
 
Ok i understand by using the sum of the moment across the x plane Ta + Td = 2.5 kN.m. What's confusing me is if i break it into separate sections AB, BC and CD, or just AB and CD to find the reactions at A and D.

also, the total angle of the shaft is zero since both ends are restrained... so the angle of AB + angle of BC + angle of CD = 0 going from left to right angle of CD is negative.. I don't get where to add in the torque at B while finding the angle from b to c.
 
Last edited:
The shaft is statically indeterminate. Have you studied how to find the unknown reactions in such a case?
 
I must correct myself, I have seen how to solve for statically indeterminate shafts but it was a single cylinder with a single torque applied to the center. The two torques is confusing me.

when i try to make my second static equation, I am not sure how to take into account both torques applied.
 
Last edited:
thanks steamking, I think I've figured it out now.
 

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