Two blocks and compressed spring

Click For Summary

Homework Help Overview

The problem involves two blocks on a frictionless surface with a compressed spring between them. The blocks are released, and the task is to determine the speed of one block and the spring constant, utilizing principles of momentum and energy conservation.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss using conservation of momentum to relate the speeds of the blocks after release. There are questions about how to treat the spring and its energy in the context of the problem. Some participants express uncertainty about the initial conditions and how to apply the equations correctly.

Discussion Status

The discussion is active, with participants exploring different approaches to the problem. Some have suggested using conservation of momentum and energy, while others are questioning how to apply these concepts effectively. There is no explicit consensus yet, but several productive lines of reasoning are being examined.

Contextual Notes

Participants note that the system starts at rest, which implies that the initial momentum is zero. There are also discussions about the relationship between the potential energy stored in the spring and the kinetic energy of the blocks, indicating a need to clarify assumptions about energy transfer.

chaotixmonjuish
Messages
284
Reaction score
0
Two blocks with masses m1 = 1.2 kg and m2 = 3.5 kg are at rest on a frictionless surface with a compressed spring between them. The spring is initially compressed by 65.0 cm and has negligible mass. When both blocks are released simultaneously and the spring has dropped to the surface, m1 is found to have a speed of 3.0 m/s.
What is the speed of m2?
What is the spring constant of the spring?

I don't even know how to start this problem. I thought about using the momentum equation, but I'm not sure how to treat the spring.
 
Physics news on Phys.org
If you thought about using conservation of momentum, good! That's what you need. For the second part realize that the final energy of both masses was once stored in the spring.
 
Well I'm trying to figure out how to use conservation of momentum.

P= 3.0*1.2+5.4*v

I'm not sure how to find the total velocity because I don't have the total momentum.
 
chaotixmonjuish said:
Two blocks with masses m1 = 1.2 kg and m2 = 3.5 kg are at rest on a frictionless surface with a compressed spring between them. The spring is initially compressed by 65.0 cm and has negligible mass. When both blocks are released simultaneously and the spring has dropped to the surface, m1 is found to have a speed of 3.0 m/s.
What is the speed of m2?
What is the spring constant of the spring?

I don't even know how to start this problem. I thought about using the momentum equation, but I'm not sure how to treat the spring.

I'm just throwing this out there for you, but since momentum of the system before equals the momentum of the system after...
 
Could I use the potential energy of a spring and set that equal to the kinetic energy of the blocks to figure out the velocity, or do I have to solve the first question in order ot find the spring constant.
 
Honestly, I don't have the whole spring thing down yet, but I think based on the fact that they begin at rest, i.e. momentum before = 0, you can solve for the velocity that you are missing. That get's you the first part. I can't help on the second part as I'd possibly give you bad or misleading advice.
 
I think based on the fact that they begin at rest, i.e. momentum before = 0, you can solve for the velocity that you are missing.

Yes, you can.

chaotixmonjuish said:
Could I use the potential energy of a spring and set that equal to the kinetic energy of the blocks to figure out the velocity, or do I have to solve the first question in order ot find the spring constant.

Once you find the missing velocity, you can use conservation of energy between the spring and the blocks to find the spring constant.
 
So initial momentum equals zero:

0=1.2*0+3.5*0


Does this mean final momentum equals
1.2*3+3.5*x=0
 
chaotixmonjuish said:
Does this mean final momentum equals
1.2*3+3.5*x=0
Yes. Realize that the two velocities will have opposite signs because the blocks shoot off in opposite directions.
 

Similar threads

Replies
17
Views
2K
  • · Replies 12 ·
Replies
12
Views
3K
  • · Replies 3 ·
Replies
3
Views
4K
Replies
8
Views
6K
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 27 ·
Replies
27
Views
10K
  • · Replies 10 ·
Replies
10
Views
4K