Two Blocks being pulled until one slips

  • Thread starter Thread starter indietro
  • Start date Start date
  • Tags Tags
    Blocks Two blocks
Click For Summary
SUMMARY

The problem involves two blocks with a static friction coefficient of 0.621 between them and a kinetic friction coefficient of 0.129 between the lower block and the floor. The lower block has a mass of 1.05 kg, while the upper block has a mass of 2.91 kg. To determine the least amount of time for the blocks to move 5.10 m without the upper block slipping, one must calculate the maximum static friction force, which is 17.7 N, and derive the common acceleration of the system. This acceleration is essential for applying kinematic equations to find the time required for the motion.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Knowledge of static and kinetic friction coefficients
  • Familiarity with kinematic equations
  • Ability to draw and analyze free body diagrams
NEXT STEPS
  • Calculate the maximum static friction force using the formula Ffs.max = uFn
  • Derive the common acceleration expression for the two blocks
  • Analyze the free body diagram of the lower block to find the net force
  • Apply kinematic equations to determine the time taken for the motion
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and friction, as well as educators looking for practical examples of motion involving multiple masses.

indietro
Messages
46
Reaction score
0

Homework Statement


The coefficient of static friction is 0.621 between the two blocks shown. The coefficient of kinetic friction between the lower block and the floor is 0.129. Force F causes both blocks to cross a distance of 5.10 m, starting from rest. What is the least amount of time in which the motion can be completed without the top block sliding on the lower block, if the mass of the lower block is 1.05 kg and the mass of the upper block is 2.91 kg?

__
|__|-->F
|_____|

Homework Equations



The Attempt at a Solution


i really have no idea how to start this problem. so i know that both the static friction between the upper and lower block will act to the left and the kinetic friction between the lower block and the floor will act to the left. I think what i ultimately need to find the the maximum acceleration the system can have right before the block slips. This acceleration can be used to find the time, using kinematic equations. So for the whole system:
Fnet = (ml +mu)a = Fext - Ffs - Ffk

I also know that the upper block will slip when the force of static friction is at its max so:
Ffs.max = uFn
= (0.621)(2.91)(9.8)
= 17.7 N
Im just not sure where to go from here...
THANKS!
 
Physics news on Phys.org
1. Find an expression for the common acceleration of the two blocks.
2. Draw a free body diagram of the bottom block only, find an expression for the net force on it when the top block is just about ready to slip. Solve to get a numerical value for the acceleration.
3. Use the appropriate kinematic equation to find the time.

In problems where two masses accelerate as one it is usually a good idea to find the common acceleration first, even if the problem is not directly asking for it.
 
Im not sure why i need to find the common acceleration of the two blocks if I am finding the acceleration for just the lower block?
 
Because you don't know the pulling force and you don't know the acceleration. You have two unknowns, so you need two equations. Also, I didn't say find the acceleration, I said find an expression for the acceleration. This expression will involve F.
 
ok i see, F being the biggest it can be before block 1 slips...?
 
Correct.
 

Similar threads

Replies
6
Views
1K
Replies
17
Views
3K
  • · Replies 18 ·
Replies
18
Views
3K
  • · Replies 18 ·
Replies
18
Views
2K
  • · Replies 45 ·
2
Replies
45
Views
7K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
15
Views
3K
Replies
13
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K