Two Blocks Connected by a Massless String Over a Pulley

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The problem involves a 6.0kg box on a frictionless 35° slope connected to a 2.0kg weight over a massless pulley. To keep the box stationary, the net force must equal zero, leading to the equation T = mgsin(θ). Calculating the tension gives T = 33.726269N. However, the discussion highlights a potential oversight regarding the forces acting on the block on the slope, suggesting that if the system were to move, it would introduce acceleration that affects the tension. Clarification is needed on whether the assumption of static equilibrium is valid in this scenario.
RadicalAlchmy
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A 6.0kg box is on a frictionless 35° slope and is connected via a massless string over a massless, frictionless pulley to a hanging 2.0kg weight. What is the tension in the string if the 6.0kg box is held in place, so that it cannot move?

m1= 6.0kg
m2= 2.0kg
θ=35°

So, for Box 1 to be held in place so that it doesn't move, the net force has to be equal to zero. If we tilt our coordinate system 35°,

Fnet,x = T + Gx
0 = T - mgsinθ
T = mgsinθ
T = (6.0kg)(9.8m/s2)sin(35°)
T = 33.726269N

That's the only way that I can think to do this question. The online assignment is telling me that I'm flat wrong. Is there something that I'm missing?
 
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Umm, You need to consider the 2 forces affecting the block on the slope, that's where you will get your tension. That is the way I understand it works. The block on the slope will start pulling the 2 kg no matter what, so if it starts moving, it will gain an acceleration and if it gains an acceleration then that means something, don't you think?
 
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