A 6.0kg box is on a frictionless 35° slope and is connected via a massless string over a massless, frictionless pulley to a hanging 2.0kg weight. What is the tension in the string if the 6.0kg box is held in place, so that it cannot move? m1= 6.0kg m2= 2.0kg θ=35° So, for Box 1 to be held in place so that it doesn't move, the net force has to be equal to zero. If we tilt our coordinate system 35°, Fnet,x = T + Gx 0 = T - mgsinθ T = mgsinθ T = (6.0kg)(9.8m/s2)sin(35°) T = 33.726269N That's the only way that I can think to do this question. The online assignment is telling me that I'm flat wrong. Is there something that I'm missing?