Two charges and electric field?

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SUMMARY

The forum discussion centers on calculating the net electric field produced by two point charges, specifically +8.5 microcoulombs at x = +3.0 cm and -21 microcoulombs at x = +9.0 cm. Using Coulomb's Law, E = kq/r², the calculated electric field at x = 0 cm is +6.2 x 10^7 N/C, while at x = +6.0 cm, it is -6.2 x 10^7 N/C. The negative sign indicates the direction of the electric field is towards the negative charge, confirming the influence of charge polarity on electric field direction.

PREREQUISITES
  • Coulomb's Law (E = kq/r²)
  • Understanding of electric field direction and magnitude
  • Basic knowledge of microcoulombs as a unit of charge
  • Familiarity with the Cartesian coordinate system
NEXT STEPS
  • Study the concept of electric field lines and their representation
  • Learn about superposition principle in electric fields
  • Explore the effects of multiple charges on electric field calculations
  • Investigate the relationship between electric fields and potential energy
USEFUL FOR

Students in physics, particularly those studying electromagnetism, as well as educators looking to clarify concepts related to electric fields and charge interactions.

Ginepri
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Homework Statement


Two charges are placed on the x axis. One charge (q1= +8.5 micro coulombs) is at x1 = +3.0cm and the other (q2 = -21 micro coulombs) is at x1 = +9.0cm. Find the net electric field (magnitude and direction) at (a) x = 0cm and (b) x = +6.0cm

Homework Equations


E = kq1/r^2

The Attempt at a Solution


(9x10^9 Nm^2/c^2)(8.5x10^-6 c) / (0.03m)^2 + (9x10^9 Nm^2/c^2)((-21)x10^-6 c) / (0.09m)^2 =

8.5x10^7 N/c + -2.3x10^7 N/c =

6.2x10^7 N/c

Answer key says -6.2x10^7 N/c, I can't figure out why the electric field is negative.
 
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Ginepri said:

Homework Statement


Two charges are placed on the x axis. One charge (q1= +8.5 micro coulombs) is at x1 = +3.0cm and the other (q2 = -21 micro coulombs) is at x1 = +9.0cm. Find the net electric field (magnitude and direction) at (a) x = 0cm and (b) x = +6.0cm

Homework Equations


E = kq1/r^2

The Attempt at a Solution


(9x10^9 Nm^2/c^2)(8.5x10^-6 c) / (0.03m)^2 + (9x10^9 Nm^2/c^2)((-21)x10^-6 c) / (0.09m)^2 =

8.5x10^7 N/c + -2.3x10^7 N/c =

6.2x10^7 N/c

Answer key says -6.2x10^7 N/c, I can't figure out why the electric field is negative.
Please state coulomb's Law as it was given to you in class, or in your textbook?
 

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