Two Closed Thermodynamic Cycles Conceptual Question

[doggieslover]

Imagine processing the gas clockwise through Cycle 1 and then counterclockwise through Cycle 1. Compare these two processes on the basis of the heat energy transferred to the gas in the entire cycle.
Choose the correct comparison symbol.
Q_clockwise for Cycle 1 <,=,> Q_counterclockwise for Cycle 1.

So I know that W_clockwise for Cycle 1> W_counterclockwise for Cycle 1. and Delta U = Q - W

so is it > ?


Imagine processing the gas clockwise through Cycle 1 and then clockwise through Cycle 2. Compare these two processes on the basis of the heat energy transferred to the gas in the entire cycle.
Choose the correct comparison symbol.
Q_clockwise for Cycle 1 <,=,> Q_clockwise for Cycle 2

I know that W_clockwise for Cycle 1= W_clockwise for Cycle 2

so Would the answer be Q_clockwise Cycle 1 is equal to Q_clockwise Cycle 2?

 

[kuruman]

You know that the net work done by the gas is positive when the cycle is clockwise (CW) and negative when the cycle is counterclockwise (CCW). Since $\Delta U = 0$ over a closed cycle, it follows that $Q_{\text{Net}}=W_{\text{Net}}$ regardless of whether the cycle is CW or CCW. However, those two equal numbers are both positive in the CW case and both negative in the CCW case. Thus, $$Q_{\text{Net,CW}}=W_{\text{Net,CW}}>Q_{\text{Net,CCW}}=W_{\text{Net,CCW}}$$because positive numbers are greater than negative numbers. It also follows that $$Q_{\text{Net,CW}}=W_{\text{Net,CW}}=|Q_{\text{Net,CCW}}|=|W_{\text{Net,CCW}}|.$$