Two conducting spheres connected by conducting wire.

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SUMMARY

The discussion focuses on calculating the ratio of electric fields at the surfaces of two conducting spheres connected by a conducting wire. Given the spheres have radii r1 and r2, and are separated by a distance much greater than their radii, the electric fields can be expressed using the formula E = kq/r^2. The final conclusion is that the ratio of the electric fields at the surfaces of the spheres is r2/r1, derived from the equilibrium charges q1 and q2 on the spheres.

PREREQUISITES
  • Understanding of electric fields and Coulomb's law
  • Familiarity with Gaussian surfaces and Gauss' Law
  • Knowledge of conducting spheres and charge distribution
  • Basic algebra for manipulating ratios and equations
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  • Explore the concept of electric field strength and its dependence on charge and distance
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Homework Statement


Two spherical conductors of radii r1 and r2 are separated by a distance much greater than the radius of either sphere. The spheres are connected by a conducting wire. The charges on the sphere are in equilibrium are q1 and q2 respectively, they are uniformly charged. Find the ratios of the electric fields at the surfaces of the spheres.


Homework Equations


∫E.dA=q/ε


The Attempt at a Solution


Since the distance they are separated is much greater than the radius of the two spheres, the whole system is essentially a a straight line. I want to make use of the eqn in 2 but can't seem to apply it. I know that for a straight line the gaussian surface is a cylinder but i don't know how to proceed.
 
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I don't think you really need to apply Gauss' Law here specifically. The equation for electric field is E = kq/r^2

So essentially you're looking at the electric field at the surface of one sphere due to the charge on the other.
 
NewtonianAlch said:
I don't think you really need to apply Gauss' Law here specifically. The equation for electric field is E = kq/r^2

So essentially you're looking at the electric field at the surface of one sphere due to the charge on the other.

The answer is r2/r1. No matter what I'm doing i always have the variables q1 q2 and r1^2 and r2^2 inside my ratio...
 

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