Two Converging Lense Questions

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For a converging lens with focal length f, achieving an image with a magnification of one is impossible, as this would require the object distance to equal the image distance, resulting in a contradiction in the lens formula. While a single converging lens cannot produce a non-inverted image, it can create a virtual image when the object is placed between the focal point and the lens, leading to a magnified image. The discussion highlights the geometric principles involved in lens behavior, emphasizing that inverted images correspond to negative magnification. Overall, the consensus is that while virtual images can be non-inverted, a magnification of one cannot be achieved with a single converging lens. Understanding these principles is crucial for optics applications.
JM2107
For a lens of focal length f, what value of the distance between the object and the lens[D0] would give an image with a magnification of one?

Is it possible to obtain a non-inverted image with a converging spherical lens? Explain please?

Any response would be greatly appreciated, and I would like to thank anyone for their response to this thread in advance.
 
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Hi JM2107,
to answer questions like this, you could use use 2 methods:
1) Draw 3 rays, remembering that...
... focal ray becomes parallel ray
... parallel ray becomes focal ray
... central ray is not refracted
2) Use the Law of lenses: 1/o + 1/i = 1/f
where
o = distance of object from lens
i = distance of image from lens
f = focal length

Got it? :wink:
 
It is not possible to obtain a non inverted image using a single converging lens. It is therefore not possible to obtain a magnification of 1, though it is possible to obtain a magnification of -1. (Inverted images have a negative magnification by convention).

The reason for this is purely geometrical. Arcnets outlined a standard graphical method of seeing why this is.
 
Originally posted by Claude Bile
It is not possible to obtain a non inverted image using a single converging lens.
R u sure? How about a virtual image? See here...

www.lightlink.com/sergey/java/java/clens/[/URL]
 
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Here's the answer:

Yes, it is possible to obtain a non-inverted image with a converging lens. As long as the object is between the focal length point and the lens it is possible. Of course this would be a virtual image and the image would be magnified.


m=-d(image)/d(object)

If m=1 than we have an equation where we can put d (object) = - d (image). Since 1/f = 1/d (object) + 1/d (image) and since d (object) = - d (image), therefore 1/f = 0

So there is no distance that would give a magnification of one.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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