Two covariant derivatives of a vector field

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SUMMARY

The discussion focuses on the computation of the covariant derivative of a vector field, specifically the second derivative expressed as V_{a;b;c}. The correct formulation involves the Christoffel symbols, which are essential for the proper calculation of derivatives in curved spaces. The general definition provided is V_{a_1\ldots a_k;b}= V_{a_1\ldots a_k,b}-\sum_{i=1}^k \Gamma^f_{ba_i}V_{a_1\ldots a_{i-1}fa_{i+1}\ldots a_k}. This definition serves as a natural extension of the covariant derivative to tensors of order k, emphasizing that it does not derive solely from the vector case.

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  • Familiarity with Christoffel symbols and their role in tensor calculus
  • Knowledge of tensor notation and operations
  • Basic principles of curved space and manifold theory
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[tex]V_{a;b} = V_{a,b} - \Gamma^d_{ad}V_d[/tex]

Now take the second derivative...

[tex]V_{a;b;c} = (V_{a;b})_{,c} - \Gamma^f_{ac}V_{f;b} - \Gamma^f_{bc}V_{a;f}[/tex]

But I have no idea how to get the parts with the Christoffel symbols.

[tex]V_{a;b;c} = (V_{a;b})_{,c} - \Gamma^f_{(a;b)c}V_{af} = (V_{a;b})_{,c} - \Gamma^f_{ac}V_{af;b}[/tex]..?

Yes the above is clearly wrong but how is this supposed to be done?
 
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You should start with the following general definition:

[tex]V_{a_1\ldots a_k;b}= V_{a_1\ldots a_k,b}-\sum_{i=1}^k \Gamma^f_{ba_i}V_{a_1\ldots a_{i-1}fa_{i+1}\ldots a_k}[/tex]

(with understanding that there is no i-1 for i=1)

Simply take it as a definition of the covariant derivative of a covariant tensor of order k. This definition is a natural extension of the covariant derivative to tensors, but it does not follow from the definition of the covariant derivative of vectors. It will follow as a unique extension satisfying certain natural requirements (sometimes explicit, sometimes implicit, depending on the author), but it does not follow from the formula alone.
 
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